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3 years ago

Determine if the two triangles are congruent. If they are, state how you know. SAS , ASA, AAS, SSS or HL

Mathematics

1 answer:

Mandarinka [93]3 years ago

5 0

Step-by-step explanation:

1. SAS

2. SSS

3. RHS

4. SAS

5. RHS

6. SAS

7. ASA

8. SAS

9. ASA

10. SSS

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I will give brainliest to the first person to answer the question! Please be correct and please help <33

Setler [38]

Answer:

112.25

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the radius of a cylinder with a volume of 3,165.12 cubic centimeters and a height of 7 centimeters?

leonid [27]

Answer:

Radius = 12 cm

Step-by-step explanation:

Given:

Volume of the cylinder is, $V=3165.12$ cm³

Height of the cylinder, $h= 7$ cm

Let the radius be $r$

Using the formula for volume of cylinder,

$V=\pi r^2h$

Plug in 3165.12 for $V$ , 7 for $h$ and solve for $r$ .

$3165.12=\pi r^2(7)\\3165.12=\frac{22}{7}\times 7\times r^2\\3165.12=22r^2\\r^2=\frac{3165.12}{22}\\r^2=143.869\\r=\sqrt{143.869}=11.99\approx=12\textrm{ cm}$

Therefore, the radius of the cylinder is nearly 12 cm.

7 0

3 years ago

Find the minimum distance between the point (-3,2) and the line y = -x + 1

Natasha2012 [34]

The minimum distance between the point(-3,2) and the line y = -x + 1 is $\sqrt{2}$ units.

<h3>What is a line segment?</h3>

The line that joins two points on a cartesian plane is a line segment.

Analysis:

The formula for calculating distance between a line and a point is

d = $\frac{Ax1 + By1 + c}{\sqrt{A^{2} + B^{2} } }$

where A = coefficient of x term of the line, B = coefficient of y in the line and C is the constant term of the line.

x1 and y1 are coordinates of the point.

for the line y = -x + 1 which is = y + x -1 = 0, A = 1, B = 1, C = -1, x1 = -3, y = 2
d = $\frac{1(-3) + 1(2) + (-1)}{\sqrt{(-3)^{2} + 2^{2} } }$ = $\sqrt{2}$ units

In conclusion, the distance between the point and the line is $\sqrt{2}$ units

Learn more about distance between line segments: brainly.com/question/2437195

#SPJ1

4 0

2 years ago

Simplify each expression using the proper order of operations. please help thank you so much :)

Tasya [4]

Answer:

$\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4$

$12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}$

$\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12$

$7^2 - 5* 8+1 = 10$

$(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18$

Step-by-step explanation:

<em>Required: Solve the expressions using proper operation order</em>

To solve this, we'll make use of BODMAS

--------------------------------------------------------------------------------------------------------

$\frac{41 - 3^2}{\sqrt{36} * 3 - 26}$

Evaluate all squares and square roots

$\frac{41 - 3*3}{\sqrt{36} * 3 - 26}$

$\frac{41 - 3*3}{6 * 3 - 26}$

Evaluate the numerator (Start by multiplying 3 * 3)

$\frac{41 - 9}{6 * 3 - 26}$

Subtract 9 from 41

$\frac{32}{6 * 3 - 26}$

Evaluate the denominator (Start by multiplying 6 * 3)

$\frac{32}{18 - 26}$

$\frac{32}{-8}$

Divide 32 by -8

-4

Hence;

$\frac{41 - 3^2}{\sqrt{36} * 3 - 26} = -4$

--------------------------------------------------------------------------------------------------------

$12 + 3\sqrt{8} * (9 - 2)$

Start by evaluating the bracket

$12 + 3\sqrt{8} * 7$

Then evaluate the multiplication

$12 + 21\sqrt{8}$

Simplify the square root

$12 + 21\sqrt{4 * 2}$

Split the square root

$12 + 21\sqrt{4} * \sqrt{2}$

Take Square root of 4

$12 + 21 * 2} * \sqrt{2}$

$12 + 42 \sqrt{2}$

Hence;

$12 + 3\sqrt{8} * (9 - 2) = 12 + 42 \sqrt{2}$

--------------------------------------------------------------------------------------------------------

$\frac{28 - (7^2 + 3)}{-13 + 3 * 5}$

Evaluate 7²

$\frac{28 - (49 + 3)}{-13 + 3 * 5}$

Evaluate all expression in the bracket

$\frac{28 - (52)}{-13 + 3 * 5}$

$\frac{28 - 52}{-13 + 3 * 5}$

Evaluate 3 * 5

$\frac{28 - 52}{-13 + 1 5}$

$\frac{-2 4}{2}$

$-12$

Hence;

$\frac{28 - (7^2 + 3)}{-13 + 3 * 5} = -12$

--------------------------------------------------------------------------------------------------------

$7^2 - 5* 8+1$

Evaluate 7²

$49 - 5* 8+1$

Evaluate 5 * 8

$49 - 40 + 1$

$10$

$7^2 - 5* 8+1 = 10$

--------------------------------------------------------------------------------------------------------

$(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1$

Evaluate all square root and cube root

$(2 * 4) - (3 * 9) + 1$

Solve the expressions in bracket

$8 - 27 + 1$

$-18$

Hence;

$(2 * \sqrt{16}) - (\sqrt[3]{27} * \sqrt{81}) + 1 = -18$

7 0

3 years ago

Please help ASAP!!! Will give brainlist :)

Furkat [3]

Answer:

A': (2,1)

B': (5,3)

C': (4,-1)

x -----> x + 1

y -----> y - 2

4 0

3 years ago