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2 years ago

Someone please help meee I beg you

Mathematics

1 answer:

weqwewe [10]2 years ago

8 0

The answer should be -19F
Because it would drop by 3 degrees, we know hours (x). -3x. So in this case we know how many hours we are measuring 4. So plug in the number for x and you would get -12F after multiplying, then add that to the -7F to get -19F

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There is a total of 28 I wanna find out what is 5he length and width of two blanket sizes I could make

masha68 [24]

Answer

5040

Step-by-step explanation:

7 0

2 years ago

Write an algebraic

MatroZZZ [7]

Answer:

x = 115 - p

Step-by-step explanation:

generally in algebra you will use the letter "x" to represent a value you do not know, so it wants an algebraic expression for "p subtracted from 115", this can be rewritten as 115 - p. So the unknown value "x" is equal to 115 - p.

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3 years ago

If m∠JKP=3r+12 and m∠2=4r−2, what is ∠JKN?

Leokris [45]

The answer seems to be 108

8 0

3 years ago

Please help me please please : ( : (

Gala2k [10]

Answer:

They will be picked up at 2 $\frac{1}{4}$ yards above sea level

Step-by-step explanation:

Let us consider sea level as reference and positions above sea level as positive and below sea level as negative.

With respect to this reference,

the position of top most point is +17 $\frac{3}{4}$ yards

and the position of lower most point is -13 $\frac{1}{4}$ yards

⇒ The position of midpoint is $\frac{+17 \frac{3}{4} - 13 \frac{1}{4}}{2}$

= +2 $\frac{1}{4}$

∴ <u>They will be picked up at 2 $\frac{1}{4}$ yards above sea level</u>

6 0

3 years ago

The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe

WARRIOR [948]

Answer:

7536 $km^3/sec$

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

$Volume = \pi r^2h$

Where $r$ is the radius and

$h$ is the height of cylinder.

As per question statement:

$r$ = 40 km (variable)

$h$ = 2.5 (constant)

$\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h$

As $\pi, h$ are constant:

$\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec$

4 0

3 years ago