The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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Jace bought 4 cookies and 2 brownies from the bakery.
Let x represent the number of cookies and y represent the number of brownies.
Since he bought $9 worth of cookies and brownies. Each cookie costs $0.75 and each brownie costs $3. hence:
0.75x + 3y = 9 (1)
Also, he bought twice as many cookies as brownies, hence:
x = 2y
x - 2y = 0 (2)
Solving equation 1 and 2 simultaneously gives x = 4, y = 2
Hence Jace bought 4 cookies and 2 brownies from the bakery.
There is about a 16.5% chance to pull an 8-inch piece, this is theoretical probability though. <span />
Answer: 
Step-by-step explanation:
Consider 
Substitute t= sinx
then dt = cos x dx
![[\int x^ndx=\dfrac{x^{n+1}}{n+1}+C]](https://tex.z-dn.net/?f=%5B%5Cint%20x%5Endx%3D%5Cdfrac%7Bx%5E%7Bn%2B1%7D%7D%7Bn%2B1%7D%2BC%5D)
Hence, 
