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andriy [413]
3 years ago
15

Cody said that dividing a unit fraction by a whole number is the same as multiplying the unit fractions by a unit fraction with

a whole number as a denominator​
Mathematics
2 answers:
LekaFEV [45]3 years ago
4 0

Answer:

True

Step-by-step explanation:

Hi, the statement is true, because to divide a fraction we have to turn the second fraction upside down and multiply them. Since a whole number x can be written as x/1, it also applies to the case of dividing a fraction by a whole number.

We can prove it with an example.

Dividing a unit fraction by a whole number  

1/2 ÷ 2 = (1x1) / (2x2) = 1/4

Multiplying the unit fractions by a unit fraction with a whole number as a denominator

1/2 x 1/2= (1x1) / (2x2) = 1/4

Ber [7]3 years ago
3 0

Answer: Cody is correct

Step-by-step explanation:

When a whole number is dividing a fraction, the result that will be obtained from such calculation is exactly the same result that will be obtained if you convert that whole number into a fraction, making it have "1" as it's numerator and then multiplying it by the other fraction. For clarity sake, we can use an example or two to show that Cody may not be far from the truth.

Example 1: Divide 3/4 by 2

This simply means 3/4 ÷ 2.

If we make use of a calculator to perform this operation, it will give us 3/8 as the result.

Now, Cody simply says that we can comfortably achieve this same result by converting the whole number "2" into a proper fraction, making it have "1" as the numerator and then multiplying it by 3/4.

That is:

3/4 × 1/2

= 3/8

This is a proof that Cody isn't wrong.

Example 2: Divide 4/5 by 7

The operation required is 4/5 ÷ 7 or (4/5)/7

If a good calculator is made use of to perform this calculation, the result will be 4/35.

If we apply the same principle that Cody made reference to, we will have:

4/5 × 1/7

= 4/35

These examples have shown that Cody is very correct.

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Determining Whether a Difference Is Statistically
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Using the z-distribution, it is found that:

  • The 95% confidence interval is of -1.38 to 1.38.
  • The value of the sample mean difference is of 1.74, which falls outside the 95% confidence interval.

<h3>What is the z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm zs

In which:

  • \overline{x} is the difference between the population means.
  • s is the standard error.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The estimate and the standard error are given by:

\overline{x} = 0, s = 0.69

Hence the bounds of the interval are given by:

\overline{x} - zs = 0 - 1.96(0.69) = -1.38

\overline{x} + zs = 0 + 1.96(0.69) = 1.38

1.74 is outside the interval, hence:

  • The 95% confidence interval is of -1.38 to 1.38.
  • The value of the sample mean difference is of 1.74, which falls outside the 95% confidence interval.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ2

6 0
2 years ago
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