3 years ago

Can someone help me please. -4-(4+3i)

Mathematics

1 answer:

olga2289 [7]3 years ago

5 0

Your answer would be -11.

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Can someone make me a

amm1812

Linear: y=3x-5

Non-Linear: y=x^2+3x+7

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3 years ago

Read 2 more answers

If n = 11 and p = 5 what is the value of the expression 18 - n - 2 + p

yan [13]

Answer:

Step-by-step explanation:

If n = 11 and p = 5, we can just substitute the values in for n and p in the equation 18 - n - 2 + p.

The new equation would be 18 - 11 - 2 + 5.

Using PEMDAS, we get the answer of 10.

18 - 11 = 7

7 - 2 = 5

5 + 5 = 10

Hope this helps!

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2 years ago

Giant Department Stores, Inc. purchased bedroom curtains from The Linen Company for $6.19. The markup was $4.20. What was the se

Vesna [10]

When purchased for 6.19, after mark up +4.20 = $10.39

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3 years ago

Geometry help. abcd is a parallelogram

joja [24]

The first and the 2nd one are correct because x is 21 and y is 49
3 and 4 at wrong

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3 years ago

What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?

tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

$y=x^{2}-8x+15$

we know that

The x-intercepts are the values of x when the value of y is equal to zero

For y=0

$x^{2}-8x+15=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-8x+15=0$

$a=1\\b=-8\\c=15$

substitute in the formula

$x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}$

$x=\frac{8\pm\sqrt{4}} {2}$

$x=\frac{8\pm2} {2}$

$x=\frac{8+2} {2}=5$

$x=\frac{8-2} {2}=3$

x=3, x=5

therefore

The x-intercepts are (3,0) and (5,0)

4 0

3 years ago