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Hitman42 [59]
4 years ago
9

A coin is tossed twice. Let H represents heads, T represents tails, and the combination of the two letters represent the outcome

of both tosses (e.g., if the coin landed heads on the first toss and tails on the second, we'd represent that with HT). Which of the following sets includes all possible outcomes of both tosses?
Mathematics
1 answer:
denis23 [38]4 years ago
4 0

Answer:

{HH, HT, TH, TT}

Step-by-step explanation:

The set of all possible outcomes in tossing a coin twice is;

{HH, HT, TH, TT}

In the first toss the coin may land Heads. In the second toss the coin may land Heads or Tails. This can be represented as;

HH, HT

Heads in the first and second tosses. Heads in the first toss followed by a Tail in the second toss.

In the first toss the coin is also likely to land Tails. In the second toss the coin may land Heads or Tails. This can be represented as;

TH, TT

Tails in the first toss followed by a Head in the second toss. Tails in the first and second tosses.

Combining these two possibilities will give us the set of all possible outcomes in tossing a coin twice is;

{HH, HT, TH, TT}

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Find a polynomial of degree 3 with real coefficients and zeros of -3,-1, and 4, for which f(-2)=-24
Zanzabum

We want to find a polynomial

<em>f(x)</em> = <em>a</em> <em>x</em>³ + <em>b</em> <em>x</em>² + <em>c</em> <em>x</em> + <em>d</em>

such that the roots of <em>f</em> are <em>x</em> = -3, <em>x</em> = -1, and <em>x</em> = 4, and <em>f(x)</em> takes on a value of -24 when <em>x</em> = -2.

The factor theorem for polynomials tells us that we can factorize <em>f(x)</em> as

<em>a</em> <em>x</em>³ + <em>b</em> <em>x</em>² + <em>c</em> <em>x</em> + <em>d</em> = <em>a</em> (<em>x</em> + 3) (<em>x</em> + 1) (<em>x</em> - 4)

Expand the right side:

(<em>x</em> + 3) (<em>x</em> + 1) (<em>x</em> - 4) = <em>x</em>³ - 13<em>x</em> - 12

So we have

<em>a</em> <em>x</em>³ + <em>b</em> <em>x</em>² + <em>c</em> <em>x</em> + <em>d</em> = <em>a x</em>³ - 13<em>a</em> <em>x</em> - 12<em>a</em>

<em />

In order for both sides to be equal, the coefficients of both polynomials on terms of the same degree must be equal. This means

<em>a</em> = <em>a</em> (of course)

<em>b</em> = 0 (there is no <em>x</em>² term on the right)

<em>c</em> = -13<em>a</em>

<em>d</em> = -12<em>a</em>

<em />

We also have that <em>f</em> (-2) = -24, which means

<em>f</em> (-2) = <em>a</em> (-2 + 3) (-2 + 1) (-2 - 4)

-24 = 6<em>a</em>

<em>a</em> = -4

which in turn tells us that <em>c</em> = 52 and <em>d</em> = 48.

So we found

<em>f(x)</em> = -4<em>x</em>³ + 52<em>x</em> + 48

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