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Gelneren [198K]
3 years ago
6

On a particular airline, bags checked in must weigh less than 50 pounds. Betty packed 32 pounds of clothes and five gifts that w

eigh the same amount. Which inequality can be used to find the possible weight, w, of each gift.
(A) x + 32 < 50
(B) 5x + 32 < 50
(C) 5 + x + 32 < 50
(D) x/5 + 32 < 50
Mathematics
1 answer:
andreev551 [17]3 years ago
3 0

Answer:

5x + 32 < 50

Step-by-step explanation:

On a particular airline, bags checked in must weigh less than 50 pounds. Betty packed 32 pounds of clothes and five gifts that weigh the same amount.

If each gift weighs w pounds, then the weight of five gifts will be 5w pounds and an additional 32 pounds of clothes will make it total (32 + 5w) pounds.  

Now, this total weight has to be less than 50 pounds.

Therefore, the inequality equation that can be used to find the possible weight of each gift, w is  

5x + 32 < 50 (Answer)

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A
Mashutka [201]

Answer:

3,378.70

Step-by-step explanation:

First, find the total amount Henry spends a month. 25.30 for printer ink and 52 for advertising. 25.30+52=$77.30.

Subtract what he has spent from what he has made.

3,456-77.30=3,378.70

That is his profit.

8 0
3 years ago
-3 - 8 = 19<br> —3x - 2 = 25
Delicious77 [7]

Answer:

a negative times a negative is a positive so 8×3=24/19 will give you that answer

you add -2 to the other side with 25 and get 27 then u work the rest of the problem out to solve for x

4 0
3 years ago
What is x if <br> Show your working<br> 4x+5=5x-1
weeeeeb [17]

Answer:

x=6

Step-by-step explanation:

First, add 1 on both sides

4x + 5 = 5x -1

     +1           +1

4x+6 =5x

Then, subtract 4x on both sides

4x+6 =5x

-4x      -4x

6=x

So, x equals 6

Hope this helps! :)

4 0
3 years ago
Use partial fractions to find the indefinite integral. (Remember to use absolute values where appropriate. Use C for the constan
BARSIC [14]

Answer:

125/6(In(x-25)) - 5/6(In(x+5))+C

Step-by-step explanation:

∫x2/x1−20x2−125dx

Should be

∫x²/(x²−20x−125)dx

First of all let's factorize the denominator.

x²−20x−125= x²+5x-25x-125

x²−20x−125= x(x+5) -25(x+5)

x²−20x−125= (x-25)(x+5)

∫x²/(x²−20x−125)dx= ∫x²/((x-25)(x+5))dx

x²/(x²−20x−125) =x²/((x-25)(x+5))

x²/((x-25)(x+5))= a/(x-25) +b/(x+5)

x²/= a(x+5) + b(x-25)

Let x=25

625 = a30

a= 625/30

a= 125/6

Let x= -5

25 = -30b

b= 25/-30

b= -5/6

x²/((x-25)(x+5))= 125/6(x-25) -5/6(x+5)

∫x²/(x²−20x−125)dx

=∫125/6(x-25) -∫5/6(x+5) Dx

= 125/6(In(x-25)) - 5/6(In(x+5))+C

4 0
3 years ago
Y = x2 + 4<br> y = x + 6
Nataliya [291]

Answer:

X=2

Y=8

Step-by-step explanation:

Since both equations are equal to y we can equal both equations

2x+4=x+6

x=2

y=2(2)+4

y=8

4 0
3 years ago
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