Answer:


Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
![\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D)
i)
To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.
We have to make it in steps like follows.
Cube both sides:
![\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E3%3D%5Cleft%28%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D%5Cright%29%5E3)
Simplify the radical with the cube:

Multiply by 2y+9

Simplify:

Operate the parentheses:


Subtract 3y and
:

Factor y out of the left side:

Divide by
:

ii) To find y when x=2, substitute:





Answer:
FIRST EXPRESSION:
- If
, the value of
is 
- If
, the value of
is 
- If
, the value of
is 
SECOND EXPRESSION:
- If
, the value of
is 
- If
, the value of
is 
- If
, the value of
is 
Yes, for any value of "b" the value of the first expression is greater than the value of the second expression.
Step-by-step explanation:
Substitute the given values of "b" into each expression and evaluate.
- For the first expression
, you get:
If
→ 
If
→ 
If
→ 
- For the second expression
, you get:
If
→ 
If
→ 
If
→ 
You can observe that for any value of "b" the value of the first expression is greater than the value of the second expression.
<span>To get the Least Common Multiple (LCM) of 37 and 12 we need to factor each value first and then we choose all the factors which appear in any column and multiply them:
<span><span>37: 37</span><span>12: 223 </span><span>LCM: 22337</span></span>The Least Common Multiple (LCM) is: 2 x 2 x 3 x 37 = 444</span><span> </span>
Answer: 15
Step-by-step explanation:
x-6/(x-6)+3 = x/x+5
The x in the equation is 15
Answer:
Plug in the values for x
Step-by-step explanation:
plug in x values into the equation
for example, plug -2 into the equation. y= -2(-2). y=4
So on and so forth