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alexdok [17]
3 years ago
7

Find the zero of the polynomial function x^3+8x^2-11x-18

Mathematics
1 answer:
Crank3 years ago
4 0

Answer:

The answer to your question is:  (x - 2)(x + 9)(x + 1)

Step-by-step explanation:

                                            x³  +  8x²  -  11x  -  18

find the prime factors of 18

18   2

9   3                 Try :    ± 1, ±2, ±3, ± 6,± 9

3   3

 1            

Synthetic division

                                1     8     -11    -18         2

                                       2     20    18                                            

                                1    10      9      0            First factor  ( x - 2)

                                x² + 10x + 9 = 0

                               (x + 9)(x + 1) = 0 polynomial of the form x² + bx + c

  x³  +  8x²  -  11x  -  18 = (x - 2)(x + 9)(x + 1)

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Answer:

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