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3 years ago

Critical thinking write a recursive rule for a sequence where every term is the same.

1 answer:

3 0

<span>To do this, let f(1) = 5 and f(n) = f(n-1) for n greater than 1. This is recursive rule and each term is the same because it eventually becomes f(1), which is 5.</span>

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How do you do this math??

Elis [28]

Answer:

9.6

Step-by-step explanation:

10 = 8

12 = x

then simply solve for x

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3 years ago

I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

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Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

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Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

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3 years ago

Can someone help me asap

kompoz [17]

3x + 4y <span>≥ 90

hope it helps</span>

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3 years ago

Which matrix multiplication is possible?

ruslelena [56]

Answer: D

Step-by-step explanation:

dim A=(a,b), dim B=(c,d), in order to multiply, c=b

1) dim A=(1,2) , dim B=(1,2) but 2≠1

2) dim A=(2,1) , dim B=(2,2) but 1≠2

3) dim A=(2,2) , dim B=(1,2) but 2≠1

4) dim A=(2,1) , dim B=(1,2) 1=1: result (2,2)

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2 years ago

PLZ HELP WILL PICK BRAINIEST

fenix001 [56]

Answer:

i dont know for shore but i think it is part 2

Step-by-step explanation:

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3 years ago