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3 years ago

A robot moves at a constant speed. The distance it moves and the time it spends moving are shown in this table:

Mathematics

2 answers:

Delvig [45]3 years ago

6 0

Answer:

d=0.7t

Step-by-step explanation:

I just did the question on khan academy.

Sauron [17]3 years ago

5 0

Answer:

d = 0.7*t

Step-by-step explanation:

Given data,

Time Distance

10 7

15 10.5

20 14

From analysis,

1) d1/t1 = 7/10 = 0.7

2) d2/t2 = 15/20 = 0.7

3) d3/t3 = 14/20 = 0.7

It can be analysed from the figure that, at every point d/t = 0.7

Therefore, the relationship between t and d is

d = 0.7*t

t = d/0.7

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A pair of complex numbers who have the same real and imaginary parts, but the imaginary parts have opposite signs. Their product

mixas84 [53]

Answer:

conjugate pair

Step-by-step explanation:

7 0

3 years ago

If y = 9x - 7, which of the following sets represents possible inputs and outputs of the

Lubov Fominskaja [6]

If y = 9x - 7, which of the following sets represents possible inputs and outputs of the
function, represented as ordered pairs?
{(7,9), (8, 10), (9, 11)}
{(0, -7), (1, 2), (-1, -16)}
{(1,9), (2,7), (3, 16)}
{(-7,0), (2, 1), (-16, -1)}

The answer is b {(0,-7), (1,2), (-1,-16)}

8 0

2 years ago

3. Name three colinear points?

Alex787 [66]

Answer:

ABC

Step-by-step explanation:

They are on the same line.

4 0

3 years ago

Monarch butterflies flap their wings about 12 times a second in

Inessa [10]

Remember: 60 seconds in a minute, 60 minutes in one hour.
So if butterflies flap 12 times per second, multiply that number by 60 to get how many times the butterfly flaps their wings in a minute. then, multiply that number by 60 again to get the flaps of number per minute.
12x60=720x60=43,200

8 0

3 years ago

Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is

pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

7 0

2 years ago