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3 years ago

(1+4i)−(−16+9i)

Mathematics

1 answer:

aniked [119]3 years ago

5 0

Answer:

there all cute i cant see the first one tho hella blurry she seems cute tho

Step-by-step explanation:

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During the sixth grade lunch period, Paul asks every third student who enterd the lunchroom a survey question. Which question is

Neko [114]

Answer:

Step-by-step explanation:

You would have to eliminate A because the students have not yet been to other school districts especially if it's every third. You would also have to eliminate B because well, there really isnt any other place to eat but the lunchroom because otherwise it might pose a problem, and with C it can be difficult but again, if we were to try to change something the time they take really has no impact. D would have to be the correct answer because every third student will have various favorite lunch items and will ultimately tell the school that the gross macaroni that is like...unedible is bad and needs to be taken out...immediatley.

4 0

3 years ago

Read 2 more answers

Due in 10 min help! Find t.

lys-0071 [83]

Given:

A right angle triangle with angles 45, 45, 90 degrees.

Hypotenuse of the triangle = $7\sqrt{2}$ mm

Base of the triangle = t

To find:

The value of t.

Solution:

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

Using this trigonometric ratio in the given triangle, we get

$\cos (45^\circ)=\dfrac{t}{7\sqrt{2}}$

$\dfrac{1}{\sqrt{2}}=\dfrac{t}{7\sqrt{2}}$

$\dfrac{7\sqrt{2}}{\sqrt{2}}=t$

$7=t$

Therefore, the value of t is 7 millimetres.

8 0

2 years ago

A company makes desks, coffee tables, and corner tables. Each item uses units of wood, fabric, and stuffing.

Anastasy [175]

Answer: 50x+30y+5z= 690

40x+15y+5z= 620

45x+10y+5z= 510

Step-by-step explanation: The first equation to find units of wood, the second is for the units of fabric, and the third is for the units of stuffing.

5 0

1 year ago

A random experiment was conducted where a Person A tossed five coins and recorded the number of ""heads"". Person B rolled two d

cestrela7 [59]

Answer:

(10) Person B

(11) Person B

(12) $P(5\ or\ 6) = 60\%$

(13) Person B

Step-by-step explanation:

Given

Person A $\to$ 5 coins (records the outcome of Heads)

Person $\to$ Rolls 2 dice (recorded the larger number)

Person A

First, we list out the sample space of roll of 5 coins (It is too long, so I added it as an attachment)

Next, we list out all number of heads in each roll (sorted)

$Head = \{5,4,4,4,4,4,3,3,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2,2,2,1,1,1,1,1,0\}$

$n(Head) = 32$

Person B

First, we list out the sample space of toss of 2 coins (It is too long, so I added it as an attachment)

Next, we list out the highest in each toss (sorted)

$Dice = \{2,2,3,3,3,3,4,4,4,4,4,4,5,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,6\}$

$n(Dice) = 30$

Question 10: Who is likely to get number 5

From person A list of outcomes, the proportion of 5 is:

$Pr(5) = \frac{n(5)}{n(Head)}$

$Pr(5) = \frac{1}{32}$

$Pr(5) = 0.03125$

From person B list of outcomes, the proportion of 5 is:

$Pr(5) = \frac{n(5)}{n(Dice)}$

$Pr(5) = \frac{8}{30}$

$Pr(5) = 0.267$

From the above calculations:  $0.267 > 0.03125$  Hence, person B is more likely to get 5

Question 11: Person with Higher median

For person A

$Median = \frac{n(Head) + 1}{2}th$

$Median = \frac{32 + 1}{2}th$

$Median = \frac{33}{2}th$

$Median = 16.5th$

This means that the median is the mean of the 16th and the 17th item

So,

$Median = \frac{3+2}{2}$

$Median = \frac{5}{2}$

$Median = 2.5$

For person B

$Median = \frac{n(Dice) + 1}{2}th$

$Median = \frac{30 + 1}{2}th$

$Median = \frac{31}{2}th$

$Median = 15.5th$

This means that the median is the mean of the 15th and the 16th item. So,

$Median = \frac{5+5}{2}$

$Median = \frac{10}{2}$

$Median = 5$

Person B has a greater median of 5

Question 12: Probability that B gets 5 or 6

This is calculated as:

$P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}$

From the sample space of person B, we have:

$n(5\ or\ 6) =n(5) + n(6)$

$n(5\ or\ 6) =8+10$

$n(5\ or\ 6) = 18$

So, we have:

$P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}$

$P(5\ or\ 6) = \frac{18}{30}$

$P(5\ or\ 6) = 0.60$

$P(5\ or\ 6) = 60\%$

Question 13: Person with higher probability of 3 or more

Person A

$n(3\ or\ more) = 16$

So:

$P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Head)}$

$P(3\ or\ more) = \frac{16}{32}$

$P(3\ or\ more) = 0.50$

$P(3\ or\ more) = 50\%$

Person B

$n(3\ or\ more) = 28$

So:

$P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Dice)}$

$P(3\ or\ more) = \frac{28}{30}$

$P(3\ or\ more) = 0.933$

$P(3\ or\ more) = 93.3\%$

By comparison:

$93.3\% > 50\%$

Hence, person B has a higher probability of 3 or more

7 0

2 years ago

2. A large fruit-eating bat called the black flying fox, Pteropus alecto, occupies a large mangrove swamp on Indooroopilly Islan

Svetach [21]

Step-by-step explanation:

a. P(mites OR ticks) = P(mites) + P(ticks) − P(mites AND ticks)

P(mites OR ticks) = 0.80 + 0.30 − 0.20

P(mites OR ticks) = 0.90

b. P(no ticks | mites) = P(no ticks AND mites) / P(mites)

P(no ticks | mites) = (0.80 − 0.20) / 0.80

P(no ticks | mites) = 0.75

c. If two events are independent, then P(A and B) = P(A) × P(B).

P(mites AND ticks) = 0.20

P(mites) × P(ticks) = 0.80 × 0.30 = 0.24

They are not independent.

5 0

3 years ago