Step-by-step explanation:
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You can write three equations in the numbers of nickels (n), dime (d), and quarters (q).
n + d + q = 23 . . . . . . . there are 23 coins total
0n +d -q = 2 . . . . . . . . .there are 2 more dimes than quarters
5n +10d +25q = 250 . .the total value is $2.50
The collection includes 11 nickels, 7 dimes, and 5 quarters.
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I used the matrix function of my calculator to solve these equations. You can find q by subtracting from the last equation five times the sum of the first two equations.
(5n +10d +25q) -5((n +d +q) +(d -q)) = (250) -5(23 +2)
25q = 125 . . . . . . . simplify
q = 5
From the second equation,
d = q +2 = 7
And from the first,
n = 23 -5 -7 = 11
Combine like terms.
5c = 45
Divide 5 on both sides.
c = 9
Hope this helps!
Step-by-step explanation:
∠4 = ∠1 & ∠2 = ∠3
360 - 2(98) = ∠2 + ∠3
∠3 = 164/2
∠3 = 82°
Answer:
pizzeria1
Step-by-step explanation:
Given data
pizzeria1
Diameter=16in
Radius= 16/2= 8in
Area= πr^2
Area= 3.132*8^2
Area= 201.09 in^2
pizzeria2
Diameter=15in
Radius= 15/2= 7.5in
Area= πr^2
Area= 3.132*7.5^2
Area= 176.74n^2