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2 years ago

Two similar

Mathematics

1 answer:

tamaranim1 [39]2 years ago

5 0

Answer:

The mass of the smaller cylinder is 36 grams.

Step-by-step explanation:

Given that two similar cylinders have total surface areas of 45cm² and 20cm², if the larger has a mass of 81g, the following calculation must be performed to determine the mass of the smaller one:

45 = 81

20 = X

(20 x 81) / 45 = X

1620/45 = X

36 = X

Therefore, the mass of the smaller cylinder is 36 grams.

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( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
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2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

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c=19,6
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y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
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point x=(15,8)

y is midpoint of A and D
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Y=(13,4)

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B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
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D= $\sqrt{(8)^{2}+(-4)^{2}}$
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D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

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A=5,8
D=21,0
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y1=8
x2=21
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D= $\sqrt{(16)^{2}+(-8)^{2}}$
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AD= $4 \sqrt{2}$

so we have
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BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
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(b1+b2) times 1/2 times height
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( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
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X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
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