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3 years ago

What is 5.73 rounded to the nearest tenth

Mathematics

2 answers:

agasfer [191]3 years ago

7 0

The answer is 5.7 because you can only round down not up

MariettaO [177]3 years ago

7 0

Im pretty sure its 5.7

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Y=-5x – 26 15y=3x – 18

harina [27]

Answer:

Y = − 5 x − 26

y = x /5 − 6 /5

Step-by-step explanation:

4 0

3 years ago

–12.3 – 14.2 A. 0.9 B. 26.5 C. –0.9 D. –26.5

IrinaK [193]

Answer:

-26.5

Step-by-step explanation:

-12.3 - 14.2 =

in addition or subtraction, if the signs are alike, u add them and keep the same sign

so, -12.3 - 14.2 = - 26.5

but dont get this rule confused with multiplying or dividing...because those have different rules

3 0

2 years ago

Simplify -3p3 + 5p + (-2p 2) + (-4) - 12p + 5 - (-8p3). Select the answer in descending powers of p.

BigorU [14]

-3p^3 + 5p -2p^2 - 4 - 12p + 5 + 8p^3
5p^3 - 2p^2 - 7p + 1

It is the second choice

7 0

3 years ago

Find the first and second derivatives of the function y = sin(x^2)

exis [7]

Y = sin(x^2)

Use the chain rule.

We want dy/dx.

dy/dx = cos(x^2)*2x

dy/dx = 2xcos(x^2)

Did you follow?

7 0

2 years ago

In a manufacturing process a random sample of 9 bolts manufactured has a mean length of 3 inches with a standard deviation of .3

Serggg [28]

Answer:

The correct option is (C) (2.769, 3.231).

Step-by-step explanation:

The confidence interval for mean when the standard deviation is not known is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\frac{s}{\sqrt{n}}$

Given:

$\bar x = 3\\s=0.3\\n=9\\\alpha =1-0.95=0.05$

Compute the critical value as follows:

$t_{\alpha/2, (n-1)}=t_{0.05/2, (9-1)}=t_{0.025, 8}=2.31$

**Use a t-table.

The 95% confidence interval for true mean length of the bolt is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\frac{s}{\sqrt{n}}\\=3\pm 2.31\times \frac{0.30}{\sqrt{9}}\\ =3\pm 0.231\\=(2.769, 3.231)$

Thus, the 95% confidence interval for true mean length of the bolt is (2.769, 3.231).

The correct option is (C).

7 0

2 years ago