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pogonyaev
3 years ago
5

11 more than four times a number is 39

Mathematics
1 answer:
Aliun [14]3 years ago
4 0

Hello!

Your answer is: 7

(X = "<em>A number</em>")

<em>"11 more than four times a number is 39"</em> in equation form is: 4X + 11 = 39

to solve, first subtract 11 from both sides:

4X = 28

then divide both sides by 4 to get:

X = 7

I hope this helps, and have a nice day!

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44

Step-by-step explanation:

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-7v² - 57v - 2

Step-by-step explanation:

-7v² - 49v - 2 - 8v

-7v² - 57v - 2

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Write an equation based on the following table
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Find the general solution to 3y′′+12y=0. Give your answer as y=... . In your answer, use c1 and c2 to denote arbitrary constants
lozanna [386]

Answer:

y(x)=c_1e^{2ix}+c_2e^{-2ix}

Step-by-step explanation:

You have the following differential equation:

3y''+12y=0     (1)

In order to find the solution to the equation, you can use the method of the characteristic polynomial.

The characteristic polynomial of the given differential equation is:

3m^2+12=0\\\\m^2=-\frac{12}{3}=-4\\\\m_{1,2}=\pm2\sqrt{-1}=\pm2i

The solution of the differential equation is:

y(x)=c_1e^{m_1x}+c_2e^{m_2x}   (2)

where m1 and m2 are the roots of the characteristic polynomial.

You replace the values obtained for m1 and m2 in the equation (2). Then, the solution to the differential equation is:

y(x)=c_1e^{2ix}+c_2e^{-2ix}

4 0
3 years ago
A grab bag contains 12 packages worth $.70 each, 15 packages $.40 cents each, and 25 packages worth $.30 each. what is the expec
Salsk061 [2.6K]

The expected value of the discrete distribution, if you have to pay $.50 to pick one package at random, is of -$0.08.

<h3>What is the mean of a discrete distribution?</h3>

The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.

For this problem, considering the cost of $0.5, the distribution is given as follows:

  • P(X = 0.2) = 12/(12 + 15 + 23) = 12/50 = 0.24.
  • P(X = -0.1) = 15/(12 + 15 + 23) = 15/50 = 0.3.
  • P(X = -0.2) = 23/(12 + 15 + 23) = 23/50 = 0.46.

Hence the expected value is given by:

E(X) = 0.2 x 0.24 - 0.3 x 0.1 - 0.2 x 0.46 = -$0.08.

More can be learned about the expected value of a discrete distribution at brainly.com/question/13008984

#SPJ1

8 0
2 years ago
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