Answer:
Answered
Step-by-step explanation:
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Answer:
X=3/2 and 2/3
Step-by-step explanation:
6x^2 - 13^x + 6= 0
6x^2 - 4x - 9x + 6=0
By factorising...
2x(3x - 2) - 3(3x - 2)=0
(2x - 3) (3x - 2)=0
2x - 3=0
2x=3
X=3/2
3x - 2=0
3x=2
X=2/3
Hence, X=3/2 and 2/3
<h2>
Answer: 31 & 32</h2>
Step-by-step explanation:
So we first need to assign letters to represent the numbers.
Let 'a' be the larger number and 'b' the smaller.
Now we can use this to write equations that we can solve simultaneously to find both 'a' and 'b'.
according to the question:
a + 4b = 156 [1]
a - b = 1 [2] (this is because the integers are consecutive
We can rearrange [2] to make 'a' the subject: a = b + 1 [3]
We can then substitute [3] into [1] and solve for b
(b + 1) + 4b = 156
5b = 155
b = 31
Now we can find 'a' using [3]
a = 31 + 1
a = 32
Answer:
huh
Step-by-step explanation:
The correct option is: Option (B)

Explanation:
First thing is that the difference between each number in the series with the next number is 5. It means it must be the multiple of 5. There are two options that contain multiples of 5: Option B and Option D. Now in the option D, the upper limit is 6. If we put 6 in the expression: 5(6)-2, the last term would be 28. However in the series given in the question, the last term is 33. Hence 5(7) - 2 = 35 - 2 = 33 which is Option B.
When i=1: 5(1)-2 = 3
When i=2: 5(2)-2 = 8
When i=3: 5(3)-2 = 13
.
.
When i=7: 5(7)-2 = 35-2 = 33
Hence the correct option is (B).