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vesna_86 [32]
3 years ago
11

Help is appreciated. Question is worth 15 points. Suppose that 2

Mathematics
2 answers:
GrogVix [38]3 years ago
5 0

Answer:

huh

Step-by-step explanation:

Lynna [10]3 years ago
5 0
Huh? what’s the question?
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The chances of winning the Maryland lottery are one chance in twenty-two million. The probability would be considered an example
emmasim [6.3K]

Answer:

Descriptive statistics

Step-by-step explanation:

The chances of winning the Maryland lottery are one chance in twenty-two million. The probability would be considered an example of Descriptive statistics

Descriptive statistics is referred to as the process of using a descriptive statistic. A descriptive statistic contains the quantitative summary from a sample data or information.The chances of winning the Maryland lottery are one chance in twenty-two million is an example.

6 0
3 years ago
Solve for x.<br> 4(x-3)= -2x - 4
geniusboy [140]
The answer should be x=4/3
8 0
3 years ago
Read 2 more answers
2/3 is what percent of 1/4
asambeis [7]

Answer:

267%

Step-by-step explanation:

you need to divide the second number by the first. This will give you the percentage.

2/3 ÷ 1/4 = 8/3 = 2.67 = 267%

6 0
3 years ago
2)
Elenna [48]

Parallel lines are in the same plane, never intersect, and have the same slope.

7 0
3 years ago
Total world consumption of iron was approximately 900 million tons in 1993. If consumption had increased by 2.5% each year and t
Lilit [14]

Step-by-step explanation:

We can model the annual consumption of iron by the equation

c = 900 million tons x 1.025^n, where

n is the number of years after 1993 and

c is the consumption for that year.

An estimate for the total consumption of iron can now be obtained by integrating this equation with respect to a dummy variable, x from 0 to n.

C = 900*10^6* \int\limits^n_0 {1.025^x} \, dx

This equation simplifies to

C = 900 million tons x (1.025^n - 1) / ln(1.025), where

x is a dummy variable and

C is the total consumption of iron n years after 1993.

Let R be the amount of iron remaining at n years after 1993, so

R = 480 billion tons - C

R = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

We need to find the value of n when R is 0, so

0 = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

Simplify this equation to obtain

n = 107.4

So the iron will run out in the year 1993 + 107 = 2100

6 0
2 years ago
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