Answer:
Following are the solution to this question:
Explanation:
In point 1:
Trials frequency 
calculating the main length of cryptography = 112 bit

calculating the second year value:


Currently, in average , at least half the possible sleeves is being used to verify the encryption process: 

the total time value will be 
In point 2:
In cryptography, the common name is Triple DES (3DES), which would be the symmetric-key encrypted communication algorithm (TDEAor Triple DEA), which adds 3 times per block size only with the cryptographic method Data Encryption Standard ( DES).
Algorithm:-
The key package involves four DES keys, K1, K2, and K3, each 56-bit (except parity bits), Triple DES includes. Its encoding algorithm is::

I.e. K1, DES encrypt, K2 decrypt, then K3 encrypt DES.
The reverse is the decryption:

I.e. decrypt by K3, crypt by K2, decrypt by K1.
Every three-bit authentication encrypts a 64-bit block.
Its middle procedure in each situation it's the reverse of the first operation. It improves the strength of the key second option algorithm which offers DES native support with key option 3.