Question

Divide the following polynomials, Write answer in descending powers of y. (2y to the third power + 3y squared - 4y - 5) (y + 1)

Answer 1

The first stwp for solving this expression is to multiply each term in the first parenthesis by each term in the second parenthesis (FOIL method).
2y³ × y + 2y³ + 3y² × y + 3y² - 4y × y - 4y - 5y - 5
Calculate the product of the first two numbers.
2$y^{4}$ + 2y³ + 3y² × y + 3y² - 4y × y - 4y - 5y - 5
Calculate the product of the second multiplication expression. (2y² × y)
2$y^{4}$ + 2y³ + 3y³ + 3y² - 4y × y - 4y - 5y - 5
Calculate the product of the final multiplication expression. (-4y × y)
2$y^{4}$ + 2y³ + 3y³ + 3y² -4y² - 4y - 5y - 5
Collect the like terms that contain y³.
2$y^{4}$ + 5y³ + 3y² -4y² - 4y - 5y - 5
Collect the like term that contain y².
2$y^{4}$ + 5y³ + -y² - 4y - 5y - 5
Lastly,, collect the like terms that have y.
2$y^{4}$ + 5y³ + -y² - 9y - 5
Since we cannot simplify this expression down any further,, the correct answer to your question is going to be 2$y^{4}$ + 5y³ + -y² - 9y - 5.
Let me know if you have any further questions.
:)