Answer:
The 99th percentile for a man’s arm span is 80.47 inches.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

99th percentile
X when Z has a pvalue of 0.99. So X when Z = 2.327.




The 99th percentile for a man’s arm span is 80.47 inches.
Answer:
(a) Number of committees formed if there are no restrictions = 350
(b) Number of committees formed if 2 of the women refuse to serve together = 310
Step-by-step explanation:
As per the question,
Number of women = 7
Number of men = 5
The different committees are possible if
(a) There are no restrictions
Number of committees formed
= 
= 350
(b) 2 of the women refuse to serve together
From the 350, we must subtract the number of ways those two women serve together.
If the men and women both serve together, then 1 woman serve with 4 men.
The men are chosen
,
So
The number we must subtract from the 350 is 4 × 10 = 40
∴ Number of committees formed = 350 - 40 = 310.
The answer is 1500 you divide 1 by 3 you will come up with .3 repeating then you will divide that by 4500
143.7 I believe since you take 6.80*20=136+46=2.3*20
136+46=182
182*7.65%=168.08
168.08*8.95%=153.04
153.04*6.1%=143.7
There is no b unfortunately
Find inverse of x+a
interchAnge
Inverse is
Now
- x-a=cx-d
- x-cx=a-d
- x(1-c)=a-d
- x=a-d/1-c
So
You can have any number according to this but
- c must not be 1
- a and d must not be equal .
- All three should belongs to integers set
Note:-
As there is no b given in question (May be missed in typing) Part-2 's equation can't be executed and part 3 also