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Travka [436]
3 years ago
9

Finn is baking cakes for a party. The number of cups of sugar Finn needs is proportional to the number of cakes he plans to bake

. Which statements are true about the number of cups of sugar Finn needs? Select each correct answer.
Mathematics
1 answer:
sergey [27]3 years ago
7 0
Can you please attach the options?
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Please please tell the truth I love the answers please tell them to me
DIA [1.3K]

1. A debit signifies something owed. So, that means the answer is negative.

-$40

2. A deposit means you are gaining money. So, the answer is positive.

+$225

3. Above sea level signifies to us it is above zero. So, the answer is positive.

+14000 feet

(Keep in mind, whenever they say above, it is always positive.)

4. The temperature increased, meaning that it is positive.

+40°F

5. Withdrawl implies losing money. So, the answer is negative.

-$225

6. Below sea level implies it is below zero. So, the answer is negative.

-14000 feet

8 0
2 years ago
Factor the expression using the GCF 21+15
Svet_ta [14]

Answer:

3(7+5)

Step-by-step explanation:

21+15

Each term is divisible by 3

3*7 +3*5

3(7+5)

6 0
3 years ago
I just want to know if I’m right
Svetradugi [14.3K]

Answer:

correct

Step-by-step explanation:

supplementary is when 2 angles add up to 180

8 0
3 years ago
Read 2 more answers
The heights of a group of boys and girls at a local middle school are shown on the dot plots below. 2 dot plots with number line
atroni [7]

Answer:sushi love sushi sushi is life and life is sushi

Step-by-step explanation:

8 0
3 years ago
Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt
Leni [432]
Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = \sqrt{Δx^2+Δy^2}
d₁ = \sqrt{(-2-1)^2+(1-4)^2}
d₂ = \sqrt{(x-1)^2+(y-4)^2}
d₁ = d₂
∴ \sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2} ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
 (x-1)²+(y-4)² = 18
from equatoin (1)  y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = \pm \sqrt{9} = \pm 3
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1)  or  (-2,7)












8 0
3 years ago
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