<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Answer: 59
Step-by-step explanation:
Given
2b³+5 and b=3 ⇒ 2b³+5=2(3)³+5
Simplify exponents
2(3)³+5
=2(3×3×3)+5
=2×27+5
Multiplication
=54+5
Addition
=59
Hope this helps!! :)
Please let me know if you have any questions
Answer:
Step-by-step explanation:
We khow that the equation of a circle is written this way :
(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .
Our task is to khow the values of a and b :
- We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y=
x+8 - We khow that the points P and Q are two points in the cercle
- Let Ω be the center of this cercle
- we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
- So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
- Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
- PΩ=
and QΩ=
- Let's substitute a by x and b by y
- PΩ=QΩ we substitute each distance by its expression
- After simplyfying the expressions we get finally : -12+8x-8y=0
- now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
- these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
- we substitute a by 4 and y by 2 in PΩ to get the radius
- we get r =
= 4 - so r²= 16
- then the equation is : (x-4)²+(y-2)²=16
Answer:
Generally the barrier width is 
Step-by-step explanation:
From the question we are told that
The tunneling probability required is 
The barrier height is 
The electron energy is 
Generally the wave number is mathematically represented as
![k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }](https://tex.z-dn.net/?f=k%20%20%3D%20%20%5Csqrt%7B%20%5Cfrac%7B2%20%2A%20m%20%5BV_o%20-%20E%5D%7D%7B%5C%3D%20h%5E2%7D%20%7D)
Here m is the mass of the electron with the value 
h is is know as h-bar and the value is 
So
![k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }](https://tex.z-dn.net/?f=k%20%20%3D%20%20%5Csqrt%7B%20%5Cfrac%7B2%20%2A%209.11%20%2A10%5E%7B-31%20%7D%20%5B0.4%20-%200.04%5D%20%2A%201.6%2A10%5E%7B-19%7D%7D%7B%5B1.054%2A10%5E%7B-34%7D%5E2%5D%7D%20%7D)
=> 
Generally the tunneling probability is mathematically represented as
![T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}](https://tex.z-dn.net/?f=T%20%20%3D%2016%20%2A%20%5Cfrac%7BE%7D%7BV_o%20%7D%20%20%2A%20%5B1%20-%20%5Cfrac%7BE%7D%7BV_o%7D%20%5D%20%2A%20e%5E%7B-2%20%2A%20k%20%2A%20a%7D)
So
![1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}](https://tex.z-dn.net/?f=1.0%20%2A10%5E%7B-5%7D%20%3D%2016%20%2A%20%5Cfrac%7B0.04%7D%7B0.4%20%7D%20%20%2A%20%5B1%20-%20%5Cfrac%7B0.04%7D%7B0.4%7D%20%5D%20%2A%20e%5E%7B-2%20%2A%203.0736%20%2A10%5E%7B9%7D%20%2A%20a%7D)
=> 
Taking natural log of both sides
![ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}](https://tex.z-dn.net/?f=ln%5B6.944%2A10%5E%7B-6%7D%5D%20%3D%20-2%20%2A%203.0736%20%2A10%5E%7B9%7D%20%2A%20a%7D)
=> 
=> 