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omeli [17]
3 years ago
12

What is the answer to the problem: Solve (The square root of 2x-7) = 7?

Mathematics
1 answer:
quester [9]3 years ago
4 0
The equation is 
\sqrt{2x-7}=7\\\text{Elevating to 2 the two sides of the equation we get:}\\2x-7=49\\\text{Therefore:}\\2x=49+7=56\\x=\frac{56}{2}=28\\\text{Solution : }x=28
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If 42 students were born in a state other than Texas, how many students does Mrs. Vy have in all her classes
Tanya [424]

Answer:

58

Step-by-step explanation:

7 0
3 years ago
What is the circumference of this circle given a radius of 7 in.?
EastWind [94]

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7 0
3 years ago
Read 2 more answers
Please help me solve this.
worty [1.4K]

Answer: 59

Step-by-step explanation:

Given

2b³+5 and b=3 ⇒ 2b³+5=2(3)³+5

Simplify exponents

 2(3)³+5

=2(3×3×3)+5

=2×27+5

Multiplication

=54+5

Addition

=59

Hope this helps!! :)

Please let me know if you have any questions

8 0
3 years ago
Hi :) how to do question 7 ?
Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

  • We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= \frac{-3}{2}x+8  
  • We khow that the points P and Q are two points in the cercle
  • Let Ω be the center of this cercle
  • we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
  • So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
  • Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
  • PΩ=\sqrt{(a-4)^{2}+(b-6)^{2}  } and QΩ=\sqrt{(a-8)^{2}+(b-2)^{2}   }
  • Let's substitute a by x and b by y
  • PΩ=QΩ we substitute each distance by its expression
  • After simplyfying the expressions we get finally : -12+8x-8y=0
  • now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
  • these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
  • we substitute a by 4 and y by 2 in PΩ to get the radius
  • we get r = \sqrt{(4-4)^{2}+(2-6)^{2}  } = 4
  • so r²= 16
  • then the equation is : (x-4)²+(y-2)²=16
5 0
3 years ago
Read 2 more answers
A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr
Goryan [66]

Answer:

Generally the barrier width is a = 1.9322 *10^{-9} \ m

Step-by-step explanation:

From the question we are told that

     The tunneling probability required is  T  = 1 * 10^{-5}

      The barrier height is  V_o  = 0.4 eV

       The electron energy is  E = 0.08eV

Generally the wave number is mathematically represented as

      k  =  \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }

Here m is the mass of the electron with the value  m  =  9.11 *10^{-31} \  kg

         h  is is know as h-bar and the value is  \= h = 1.054*10^{-34} \  J \cdot s

So

          k  =  \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }

=>      k = 3.073582 *10^{9}  \ m^{-1}

Generally the tunneling probability is mathematically represented as

          T  = 16 * \frac{E}{V_o }  * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}

So

        1.0 *10^{-5} = 16 * \frac{0.04}{0.4 }  * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}

=>    6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}

Taking natural log of both sides

          ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}

=>        -11.8776  = -2 * 3.0736 *10^{9} * a}

=>        a = 1.9322 *10^{-9} \ m

       

4 0
3 years ago
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