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Irina-Kira [14]
2 years ago
6

What is the value of x? (picture attached)

Mathematics
1 answer:
lozanna [386]2 years ago
6 0

x= 48

P/s: sorry. I cant explain  

ok done.thank to me :>

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Help me :,)
IrinaK [193]

Answer:

The rule of the arithmetic sequence is 13 - 2n

The 30th term is -47

Step-by-step explanation:

∵ f(n) = 11 and g(n) = -2(n - 1) = -2n + 2

∴ f(n) + g(n) = 11 + -2n + 2 = 13 - 2n

Use n = 1 , 2 , 3 , 4 to check the type of the sequence

∵ n = 1 ⇒ 13 - 2(1) = 11

∵ n = 2 ⇒ 13 - 2(2) = 13 - 4 = 9

∵ n = 3 ⇒ 13 - 2(3) = 13 - 6 = 7

∵ n = 4 ⇒ 13 - 2(4) = 13 - 8 = 5

∵ 11 , 9 , 7 , 5 is an arithmetic sequence with difference -2

∴ The rule of the arithmetic sequence is 13 - 2n

∴ The 30th term = 13 - 2(30) = -47

5 0
2 years ago
Read 2 more answers
What is 0.4% of $100
aksik [14]

0.4% = 0.004

100 * 0.004 = 0.4

4 0
3 years ago
Read 2 more answers
A​ long-distance telephone company charges a rate of cents per minute or a ​-cent minimum charge per completed​ call, whichever
LiRa [457]

Answer: 50 cents

Step-by-step explanation:

Company charges 8 cents per call and the call in question is 3 minutes. Cost is;

= 3 * 8

= 24 cents

Company however stipulates that a call is 8 cents per minute or a 50​-cent minimum charge per completed​ call, whichever is greater.

<em>50 cents is greater than the per minute total charge of 24 cents so the cost will be 50 cents.</em>

8 0
3 years ago
What logarithmic function represents the data in the table? x f(x) 25 2 125 3 625 4
Ray Of Light [21]
\bf recall\\\\&#10;log_{{  a}}{{  b}}=y \iff {{  a}}^y={{  b}}\qquad\qquad &#10;{{  a}}^y={{  b}}\iff log_{{  a}}{{  b}}=y \\\\&#10;-----------------------------\\\\&#10;thus\qquad &#10;\begin{array}{cc|llll}&#10;x&y&5^y=x\\&#10;\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\&#10;25&2&5^2=25\\&#10;125&3&5^3=125\\&#10;625&4&5^4=625\\&#10;\end{array}&#10;\\\\\\&#10;\textit{so hmmm what would that be in log notation? }\  5^y=x \iff \boxed{?}
6 0
3 years ago
Read 2 more answers
For fun question
ZanzabumX [31]
Consider the function f(x)=x^{1/3}, which has derivative f'(x)=\dfrac13x^{-2/3}.

The linear approximation of f(x) for some value x within a neighborhood of x=c is given by

f(x)\approx f'(c)(x-c)+f(c)

Let c=64. Then (63.97)^{1/3} can be estimated to be

f(63.97)\approxf'(64)(63.97-64)+f(64)
\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375

Since f'(x)>0 for x>0, it follows that f(x) must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function f(x). This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...
4 0
3 years ago
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