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Lilit [14]
3 years ago
7

Find the value of x.

Mathematics
2 answers:
KatRina [158]3 years ago
7 0

Answer:

A or B

Step-by-step explanation:

EleoNora [17]3 years ago
7 0

The value of x is 38

First, you must subtract 180 by 105 to get the bottom left corner measurement.

180-105=75

Then, you must add the two measurements you and subtract from 180 to find x

75+67=142

180-142=38

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6 0
2 years ago
A² +6² = c²<br> Find the length of c:
yanalaym [24]
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Select the correct expressions. 1 Identify each expression that represents the slope of a tangent to the curve y= * +1 at any po
Olegator [25]

The expressions which represents the slope of a tangent to the curve y=\frac{1}{x+1} at any point (x, y) are:

                                ​f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}

<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}

Given the function:

f(x)=y=\frac{1}{x+1}

When (x + h), we have:

f(x+h)=y=\frac{1}{x+h+1}

Next, we would find the derivative of f(x):

f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}

Read more on slope of a tangent here: brainly.com/question/26015157

#SPJ1

5 0
2 years ago
Whats the solution of a + 5 &gt; -7?
rosijanka [135]
A + 5 > -7....subtract 5 from both sides
a > -7 - 5
a > - 12
4 0
2 years ago
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