All categories

4 years ago

How to find length of a triangle given one side and angle equladera; triangle?

1 answer:

4 0

An equilateral triangle is a triangle with all equal sides, meaning, if the problem gives you one side, then it has given the length of all the sides because all sides lengths are equal. Given that you have one side and one angle, all sides will be the same length and no matter what all angles are the same and if correct the angles will be equal to 60 each.
I hope this helps some.

You might be interested in

The length of the rectangular basketball court is 44 feet more than the width. If the perimeter of the basketball court is 288 f

Temka [501]

Let's first say that L=W+44

and then remember that perimeter is P=2L+2W

replace the L with W+44

we then get P=2(W+44)+2W, now I'll solve it

P=2W+88+2W
P=4W+88

substitute 288 for P

288=4W+88
200=4W
50=W

so now we now how wide the court is. add 44 to find the length which gives you L=94

as always plug the numbers back into your perimeter equation to ensure L and W are correct

8 0

3 years ago

Help please, there is a big prize up for grabs

zmey [24]

1: a) -51

b) -461

2: a) 18078.415936

b) 61715.95

8 0

3 years ago

Lines AC←→ and DB←→ intersect at point W. Also, m∠DWC=138° .

mr_godi [17]

m∠DWC=138°, ∠AWB = 138°, ∠AWD = 42°, ∠BWC = 42°

Solution:

Line $\overrightarrow{A C} \text { and } \overrightarrow{B D}$ intersect at a point W.

Given $m \angle D W C=138^{\circ}$ .

Vertical angle theorem:

If two lines intersect at a point then vertically opposite angles are congruent.

To find the measure of all the angles:

∠AWB and ∠DWC are vertically opposite angles.

Therefore, ∠AWB = ∠DWC

⇒ ∠AWB = 138°

Sum of all the angles in a straight line = 180°

⇒ ∠AWD + ∠DWC = 180°

⇒ ∠AWD + 138° = 180°

⇒ ∠AWD = 180° – 138°

⇒ ∠AWD = 42°

Since ∠AWD and ∠BWC are vertically opposite angles.

Therefore, ∠AWD = ∠BWC

⇒ ∠BWC = 42°

Hence the measure of the angles are

m∠DWC=138°, ∠AWB = 138°, ∠AWD = 42°, ∠BWC = 42°.

7 0

4 years ago

8. Identify which equation is a graph of a vertical line.

Y_Kistochka [10]

Answer:

10x = 10.

Step-by-step explanation:

The equation will contain the x variable only.

4 0

3 years ago

A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s

Bas_tet [7]

Answer:

Step-by-step explanation:

$m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}$

3 0

3 years ago