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3 years ago

Combine and simplify the third set of terms 2+15a-2

Mathematics

1 answer:

Finger [1]3 years ago

6 0

2 + 15a - 2
= 15a (because 2 - 2 = 0)

hope it helps

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Jack deposited $47,323.15 in an account earning 5% interest compounded annually.

Vera_Pavlovna [14]

Answer:

Jack's final bank account amount will be $54,782.50, earning $7,459.31 in interest.

General Formulas and Concepts:
Algebra I

Compounded Interest Rate Formula: $\displaystyle A = P \bigg( 1 + \frac{r}{n} \bigg) ^{nt}$

A is final amount
P is principle amount
r is rate
n is compounded rate
t is time

Step-by-step explanation:

Step 1: Define

Identify given variables.

P = $47,323.15

r = 0.05

n = 1

t = 3

Step 2: Find Interest

[Compounded Interest Rate Formula] Substitute in variables:
$\displaystyle A = 47323.15 \bigg( 1 + \frac{0.05}{1} \bigg) ^{1(3)}$
Evaluate:
$\displaystyle A = \boxed{54782.5}$

∴ Jack will gain $7,459.31 and have a net balance of $54,782.50.

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Learn more about Algebra I: brainly.com/question/27710663

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Topic: Algebra I

5 0

1 year ago

Would appreciate someone’s help :)

Marrrta [24]

Count the squares

Side 1:5

Side 2:7

Side 3: 5

Side 4: 7

4 0

3 years ago

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ cross multiply

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

3 years ago

A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32

zavuch27 [327]

$Hypotenuse =39cm$ of right angle triangle! .

Step-by-step explanation:

Here we have , A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32 centimeters, and the length of the other leg is 25 centimeters. The student incorrectly says that the length of the hypotenuse is 7.5 centimeters. We need to find:

We have , One length as 32 cm and other as 25 cm , as

$Perpendicular = 32cm\\Base=25cm$