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slega [8]
2 years ago
5

Which factor is most important to consider when evaluating a journal article about global warming?

Chemistry
1 answer:
Studentka2010 [4]2 years ago
8 0
Since you didn't include the options, I will answer the question as well as I can: the one factor I would be considering is whether the journal is known to be biased, for example whether it's a peer-reviewed journal ( those are less biased) or whether they journal is paid by some interest group.

Otherwise I would look at whether the data is reliable, for example whether  the author cites the sources for their data
You might be interested in
The equation K2O represents the ionic bond between potassium and oxygen. What is the name of the compound?
eduard
Ten name if this compound is Potassium Oxide 
5 0
2 years ago
Read 2 more answers
What are the effects of inhalation of acetone vapor?
Ipatiy [6.2K]

Answer:

it can cause irritation in eyes throat and lungs and u can become lightheaded, or possibly fall in a coma

5 0
2 years ago
Can anyone answer this?
GenaCL600 [577]

Answer:

the answer is (a)

Explanation:

an example of +1 oxidation state is Cu2O, where oxygen is 2- and so to balance the molecule, each copper atom is +1

4 0
2 years ago
Calculate the enthalpy for the following reaction. During the reaction, the temperature changes from 42.5 C to 37 C. The specifi
Dahasolnce [82]

Answer:

q = 0.810 Kj/mol

Its an endothermic reaction

Explanation:

Enthalpy can be evaluated by using following formula -

q = m * c* \delta T

where

q is the enthalpy or change in internal energy

m is the mass in kg

c is the specific heat

and \delta T is the change in temperature

Mass of HCl is equal to 36.46 g/mol

or

Mass of HCl is equal to 0.03646  Kg/mol

Substituting the given values in above equation, we get-

q = 0.03646 * 4.04 * (42.5 - 37)\\q = 0.03646 * 4.04 * 5.5 \\

q = 0.810 Kj/mol

Enthalpy is positive thus it is an endothermic reaction

4 0
3 years ago
At a certain temperature, 0.760 mol SO3 is placed in a 1.50 L container. 2SO3(g) = 2SO2(g) + O2(g)At equilibrium, 0.130 mol O2 i
olganol [36]

Answer:

K_c=0.0867

Explanation:

Moles of SO₃ = 0.760 mol

Volume = 1.50 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.760}{1.50\ L}

[SO₃] = 0.5067 M

Considering the ICE table for the equilibrium as:

\begin{matrix} & 2SO_3_{(g)} & \rightleftharpoons & 2SO_2_{(g)} & + & O_2_{(g)}\\At\ time, t = 0 & 0.5067 &&0&&0 \\ At\ time, t=t_{eq} & -2x &&2x&&x \\----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:- &0.5067-2x&&2x&&x\end{matrix}

Given:    

Equilibrium concentration of  O₂ = 0.130 mol

Volume = 1.50 L

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.130}{1.50\ L}

[O₂] = x = 0.0867 M

[SO₂] = 2x = 0.1733 M

[SO₃] = 0.5067-2x = 0.3334 M

The expression for the equilibrium constant is:

K_c=\frac {[SO_2]^2[O_2]}{[SO_3]^2}  

K_c=\frac{(0.3334)^2\times 0.0867}{(0.3334)^2}

K_c=0.0867

5 0
3 years ago
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