All categories

4 years ago

If 40.0 grams of zinc react with excess hydrochloric acid, how many grams of zinc chloride will be produced?

Chemistry

1 answer:

ludmilkaskok [199]4 years ago

6 0

Answer:

Attached is the solution to the question

Explanation:

You might be interested in

Which types of orbitals are found in the principal energy level n = 2?

AfilCa [17]

Remember this:

1) n is principal quantum number and represents the energy level.

2) l is the second quantum number and represent the type of orbital.

3) l can take values from 0 to n - 1

4) each number of l is associated with a type of orbital. This table shows the equivalence:

l number       type of orbital

0                    s

1                    p

2                    d

3                     f

With that, you can tell that n = 2 permits l = 0 and 1, which is orbitals s and p.

Therefore, the answer is the option D) s, p.

3 0

3 years ago

Read 2 more answers

Gold has a density of about 20g/mL. If I measured out 2mL of gold, I would expect it to have a mass of about ___ grams.

yan [13]

The answer is 40 grams. If gold is 20 grams per mL and you have 2 mLs, you get 40 grams of gold. Just add 20 + 20 or multiply 2 x 20 to get 40.

4 0

3 years ago

If there are 80 liters of argon gas in a piston and the piston expands the gas until its volume is 2000 liters with a pressure o

Mice21 [21]

Answer: The correct answer is A. 11.5 atm. The temperature is held constant at 293 K, therefore, we can use Boyle's Law to determine the initial pressure. Boyle's Law states that there is an inverse relationship between pressure and volume of gases. Therefore, as volume increases, the pressure will decrease and vice versa.

Further Explanation:

Boyle's Law can be mathematically expressed as:

$P_{initial}V_{initial}\ = P_{final}V_{final}$

In this problem, we are given the values:

P(initial) = ?

V(initial) = 80 L

P (final) = 0.46 atm

V (final) = 2000 L

Plugging in these values into the equation:

$P_{initial}(80 \ L) = \ (0.46 \ atm)(2000 \ L)\\P_{initial} \ = \frac{(0.46 \ atm) \ (2000 \ L)}{80 \ L}\\P_{initial}\ = 11.5 atm\\$

The initial pressure was 11.5 atm. Since the volume increased or expanded, the space where the gas particles move is bigger, so the frequency of collisions with the wall of the container and with other particles are effectively decreased. This, therefore, decreases the pressure from 11.5 to 0.46 atm.

Learn More

Learn about Charles' Law brainly.com/question/1421697
Learn about Ideal Gas Law brainly.com/question/6534668
Learn about Gay - Lusaac's Law brainly.com/question/1358307

Keywords: gas, Boyle's Law, Ideal Gas Law

7 0

4 years ago

What is the electron configuration of Ba

Marizza181 [45]

(Xe) 6s2 is the ec of ba

4 0

3 years ago

If the reactants of a reaction are HCI and NaOH, what could be a product?

Nutka1998 [239]

Answer

HCl+NaOH=NaCl+H2O (NaCl+H20)=the product

is a double substitution reaction

so the product ,one of them will be or Nacl or Water(H2O)

6 0

2 years ago