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geniusboy [140]
3 years ago
8

How can u show that two objects are proportional using a graph

Mathematics
2 answers:
ruslelena [56]3 years ago
7 0
You can show that (y) is proportional to (x) by writing:

y\propto x

This would mean that:

y=kx

Whereby (k) would be the constant of proportionality.

This value can be an element of a real number.

k∈R

What are real numbers?

Integers, rational numbers and irrational numbers.

Example of a graph which would show that 2 objects are proportional:

y=2x
Tcecarenko [31]3 years ago
4 0
There is a directly proportional relationship, and an indirect proportional relationships.

A directly proportional relationship graph will always be a linear line.
The graph of a indirectly proportional will be a curve.

Directly proportional equation: y = kx
Indirectly proportional equation: xy = k

where k is the constant of proportionality.

I have attached a graph of them so you can better understand it :)

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laila [671]

Answer:

235.3$ for part a

7 0
3 years ago
Can someone plz help me dont know the awnser
Bumek [7]
The area of the right triangle = \frac{1}{2}bh

b = base = SV = 12.3
h = hight = HL = 24.6
A = area
\frac{1}{2}bh = A
\frac{1}{2}(12.3)(24.6) = 151.29
4 0
4 years ago
Mary Ann and Abigail were shopping for prom shoes and wondered how the prices at Payless compared to the prices at Famous footwe
Komok [63]

Answer:

Step-by-step explanation:

how the prices at Payless compared to the prices

at Famous Footwear. At each store, they randomly

selected 30 pairs of shoes and recorded the price of

each pair. The table shows summary statistics for

the two samples of shoes.28

Store

Mean

SD

Famous Footwear

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Payless

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Do these data provide convincing evidence at the

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a =

7 0
3 years ago
Prove the following statement.
gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form 2k+1 where k\in \mathbb{Z}. Consider the following cases.

Case 1. If k is even we have: (2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1.

If we denote by m=2s^2+2 we have that (2k+1)^{2}=8m+1.

Case 2. if k is odd we have: (2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1.

If we denote by m=2s^{2}+24s+1 we have that (2k+1)^{2}=8m+1

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

6 0
3 years ago
Mercury orbits the Sun in 87 24/25 earth days. Venus orbits the Sun in 224 7/10 earth days and Mars orbits the sun in 686 49/50
Rufina [12.5K]
87 24/25.......24/25 = 0.96......answer is 87.96

224 7/10....7/10 = 0.7....answer is 224.7

686 49/50...49/50 = 0.98...answer is 686.98
7 0
3 years ago
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