First you need to subtract 471.41 and 397.46.
471.41 - 397.46= 73.95
The tenths place is the number after the decimal. In number 73.95, the number in the tenths place would be 9. The answer would be C) 74.
(Let me know if you don't understand. I'll try to explain it in more detail.)
On day 3, the chart meets up at the same point, so on that day they will have had the same number left.
Step-by-step explanation:
1. AD/DB=CE/EB
given
2. AD/DB+1=CE/EB+1
Addition Property of Equality
3. AD+DB/DB=CE+EB/EB
using common denominators
4. AB = AD + DB
CB = CE + EB
segment addition
5. AB/DB=CB/EB
Substitution Property of Equality
6.ABC DBE
Reflexive Property of Congruence
7. ABC ~ DBE
SAS similarity criterion
<span>8. </span>
Corresponding angles of similar triangles are congruent.
9. DE|| AC
<span>If the corresponding angles formed by </span>
It looks like your equations are
7M - 2t = -30
5t - 12M = 115
<u>Solving by substitution</u>
Solve either equation for one variable. For example,
7M - 2t = -30 ⇒ t = (7M + 30)/2
Substitute this into the other equation and solve for M.
5 × (7M + 30)/2 - 12M = 115
5 (7M + 30) - 24M = 230
35M + 150 - 24M = 230
11M = 80
M = 80/11
Now solve for t.
t = (7 × (80/11) + 30)/2
t = (560/11 + 30)/2
t = (890/11)/2
t = 445/11
<u>Solving by elimination</u>
Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,
7M - 2t = -30 ⇒ -10t + 35M = -150 … (multiply by 5)
5t - 12M = 115 ⇒ 10t - 24M = 230 … (multiply by 2)
Now combining the equations eliminates the t terms, and
(-10t + 35M) + (10t - 24M) = -150 + 230
11M = 80
M = 80/11
It follows that
7 × (80/11) - 2t = -30
560/11 - 2t = -30
2t = 890/11
t = 445/11