<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Answer:
do you go to garcia middle school 9 feet is the answer
Step-by-step explanation:
3/4 of 7 pints were used. of, in this case, means to multiply. 3/4 x 7= 21/4= 5 and 1/4 pints. Now we subtract 5 and 1/4 (because this is how much was used) from 7. 7- 5 and 1/2 = 1 and 1/2
If you have questions, feel free to ask.
We can compare the two units or object performances by that.... even in the case of magnitude lower than zero....
