<img src="https://tex.z-dn.net/?f=%20%7B16%7D%5E%7Bx%7D%20%3D%20%20%7Bx%7D%5E%7B2%7D%20" id="TexFormula1" title=" {16}^{x} = {x

TiliK225 [7]

3 years ago

}^{2} " alt=" {16}^{x} = {x}^{2} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

AURORKA [14]3 years ago

6 0

Answer:

No soluction, cannot simplfy farther

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Are the lines x -2y = -6 And 4y + 4 = 2x perpendicular?

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2 years ago

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<img src="https://tex.z-dn.net/?f=%20%5Cint%20%5Cfrac%7Bdx%7D%7Bxln%5E%7Bp%7Dx%20%7D" id="TexFormula1" title=" \int \frac{dx}{xl

Eva8 [605]

Substitute $u=\ln x$ , so that $\mathrm du=\dfrac{\mathrm dx}x$ . The integral is then equivalent to

$\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\int\frac{\mathrm du}{u^p}=\begin{cases}\dfrac{u^{p+1}}{p+1}+C&\text{for }p\neq1\\\\\ln|u|+C&\text{for }p=1\end{cases}$

Then transforming back to $x$ gives

$\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\begin{cases}\dfrac{\ln^{p+1}x}{p+1}+C&\text{for }p\neq1\\\\\ln|\ln x|+C&\text{for }p=1\end{cases}$

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3 years ago

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$2 - 4(x + 7) = 3 + 2 (x + 2)\\\\2-4x-28=3+2x+4\\\\6x=-33\\\\x=-\dfrac{33}{6}=-\dfrac{11}{2}$