Answer:
there are only 4 whole numbers whose squares and cubes have the same number of digits.
Explanations:
let 0, 1, 2 and 4∈W (where W is a whole number), then
, ,
, .
You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits
B
Step-by-step explanation:
x = 15
If you have any questions about the way I solved it, don't hesitate to ask
2500
there you go haha