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3 years ago

How to find instantaneous and average velocity?

1 answer:

5 0

Average velocity is equal to the change in distance / change in time :

v(avg) = s / t

that's the average distance, but at some point the object could have moved faster / slower and we want to see the instantaneous velocity. The principal is the same. You take a a little piece of the road for a little piece if time and get the avg velocity of the tiny part of the road. But this way it will be not the exactly speed at that moment, it will be just the avg speed in the little fragment. So we must add limits. What will be the velocity for so tiny part of time that it approaches zero?
We get :

lim s/t = ds/dt
t->0

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Gemiola [76]

Answer: (D) bottom right graph

Step-by-step explanation:

The vertex form of a quadratic equation is: f(x) = a(x - h)² + k, where

(h, k) is the vertex
|a| is the vertical stretch
sign of "a" determines the direction of the parabola

Given g(x) = (x - 3)² - 5

vertex (h, k) = (3, -5)
vertical stretch |a| = 1
sign of "a" is positive so parabola points up

The only graph that satisfies all of these conditions is the bottom right.

7 0

3 years ago

EXPERTSSSS HELP (q.5)

Ostrovityanka [42]

Answer:

not paying 20% means that she DID pay %80

Step-by-step explanation:

4 0

3 years ago

The perimeter of any rectangle is the sum of its lengths and widths. The area of any rectangle is the length l times the width w

kkurt [141]

A. 2(l)+2(w)=P

B. lw=A

C. 2(14) + 2(8) = P
28 + 16 = P
44 = P

D. Im going to assume the rectangle shown is the same as C...
14 x 8 = A
112=A

Hope this helps!

4 0

3 years ago

This is stupid I know lol but I'm having a hard time remembering the difference between a histogram and a bar graph. Can someone

Y_Kistochka [10]

In Bar Graphs;

- Bars have equal space

- One the y-axis, we have numbers & on the x-axis, we have data which can be anything.

In Histograms;

- Bars are fixed

- On the y-axis, we have numbers & and on the x-axis, we have data which in continuous & will always be number.

An easy way you can remember the difference is looking at the spaces of the bars.

A bar graph has gaps

A histogram has no gaps.

6 0

3 years ago

Grade 10 math help please. Please show work

masha68 [24]

Answer:

43.94?

Step-by-step explanation:

I think if you use inverse cos you should get the correct number. So, to find cos, you need to know the adjacent side and the hypotenuse. Here, the reference angle would be the person holding the kite. The distance from the person to the barn is the adjacent side, which is 18. The string of the kite, I assume, would be 25.

cos(∅) = $\frac{18}{25}$

cos(∅) = 0.72

cos⁻¹(0.72) = 43.94

I don't know if that's what you're looking for, but... If it's not correct, lmk so I can rewrite it. :)

4 0

3 years ago