All categories

3 years ago

How many solutions are there to the equation y = 14x – 9? Plz HELP

Mathematics

1 answer:

dem82 [27]3 years ago

8 0

D is correct because you could put in a value for x and get a true value for y

exg
x=3
y=14(3)-9
y=42-9
y=33

You might be interested in

How would 350 percent be written as a simplified fraction

Sauron [17]

Divide by 100. 350/100=3.5 which is 3 and 1/2

4 0

3 years ago

Read 2 more answers

10. A polyhedron has 5 faces and 9 edges. How many vertices does it have?

Ksivusya [100]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write each expanded expression as a power. 1.7 x 1.7 x 1.7 =

zhuklara [117]

Answer:

1.7^3

Step-by-step explanation:

i cannot see your answer options so I hope this helps!!!!

3 0

3 years ago

Solve for v. 14 − 10v + 11 = 20v + 5(–7v − 11) v =

AlexFokin [52]

Answer:

v = -16

Step-by-step explanation:

→Distribute the 5 to (-7v - 11):

14 - 10v + 11 = 20v - 35v - 55

→Add like terms:

25 - 10v = -15v - 55

→Add 15v to both sides:

25 + 5v = -55

→Subtract 25 from both sides:

5v = -80

→Divide both sides by 5:

v = -16

7 0

3 years ago

Read 2 more answers

Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> (1 point)

sesenic [268]

Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

Step-by-step explanation:

We have , two vectors u = <-5, -4>, v = <-4, -3> or , $u = -5i-4j , v=-4i-3j$

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

$u.v =|u|(|v|)cosx$ , where x is angle between u & v !

⇒ $u.v =|u|(|v|)cosx$

⇒ $cosx =\frac{u.v}{|u|(|v|)}$

Now , $u.v = (-5i-4j)(-4i-3j)$

⇒ $u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)$

⇒ $u.v = 20+12$ { $i(j) = j(i) =0$ }

⇒ $u.v = 32$

Now , Modulus of any vector $r = xi+yj$ is $|r| = \sqrt{x^{2}+y^{2}}$ So ,

$|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5$

Putting all these values in equation $cosx =\frac{u.v}{|u|(|v|)}$ we get:

⇒ $cosx =\frac{32}{5(\sqrt{41})}$

⇒ $cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})$

⇒ $x =cos^{-1}(1)$ { $cos0 = 1$ }

⇒ $x =0$ °

Therefore , Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

8 0

3 years ago