Answer:
Both triangles are right triangles because the angle d is 90 degrees in both sides
3 ^ 2 - 2.25^2 = 1.98
4^2 - 1.98^2 = 3.48
x = 3.48
i-okay,whats yoour problem? maybe i can help :D
Answer:
y=-7x+16
Step-by-step explanation:
y-y=m(x-x1)
y-2=-7(x-2)
y-2=-7x+14
+2 +2
y=-7x+16
Answer:
Answer: Third option is the right answer.
Step-by-step explanation:
First we the write the expression
Now teacher says that the product of these polynomials will result in the sum of 
Now the teacher ask if we put the value of a = 2x and b = 1 then what will be the expression look like.
![(2x+1)\left [ (2x)^{2}+(1^{2})-(2x)(1)\right ]](https://tex.z-dn.net/?f=%282x%2B1%29%5Cleft%20%5B%20%282x%29%5E%7B2%7D%2B%281%5E%7B2%7D%29-%282x%29%281%29%5Cright%20%5D)
=
So third option is looking like our expression.
Answer:
Solutions are 2, -1 + 0.5 sqrt10 i and -1 - 0.5 sqrt10 i
or 2, -1 + 1.58 i and -1 - 1.58i
(where the last 2 are equal to nearest hundredth).
Step-by-step explanation:
The real solution is x = 2:-
x^3 - 8 = 0
x^3 = 8
x = cube root of 8 = 2
Note that a cubic equation must have a total of 3 roots ( real and complex in this case). We can find the 2 complex roots by using the following identity:-
a^3 - b^3 = (a - b)(a^2 + ab + b^2).
Here a = x and b = 2 so we have
(x - 2)(x^2 + 2x + 4) = 0
To find the complex roots we solve x^2 + 2x + 4 = 0:-
Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2
= -1 +/- (sqrt( -10)) / 2
= -1 + 0.5 sqrt10 i and -1 - 0.5 sqrt10 i
