<span>The sum of two numbers is 48.
a + b = 48
;
If one third of one number is 5 greater than one sixth of another number,
a = b + 5
multiply both sides by 6, cancel the fractions
2a = b + 30
2a - b = 30
</span><span>use elimination to solve this
a + b = 48
2a - b =30
-------------Addition eliminates b, find a
3a = 78
a =
a = 26
then
26 + b = 48
b = 48 - 26
b = 22</span>
Answer:
7 . 4 + 6 - 12 : 4 = 31
Step-by-step explanation:
* To solve this problem lets revise the order of operations in
mathematics
- The operations are:
# Addition
# Subtraction
# Multiplication
# Division
# Exponentiation
# Grouping ⇒ Parenthesis or brackets
- The order of these operations is:
# Parenthesis
# Exponents
# Multiplication and Division which comes first from left to right
# Addition and Subtraction which comes first from left to right
- There is a word made from the first letter of each operation
PEMDAS to remember the order of operations
* Lets solve the problem
∵ 7 . 4 + 6 - 12 : 4
∵ The (.) means multiply the numbers
∵ The symbol (:) means divided the numbers
∴ At first multiply 7 by 4 and divide 12 by 4
∴ (7 × 4) + 6 - (12 ÷ 4)
∴ 28 + 6 - 3
∵ Addition comes before subtraction from the left
∴ (28 + 6) - 3
∴ 34 - 3 = 31
∴ 7 . 4 + 6 - 12 : 4 = 31
Answer:
It's a true solution.
Step-by-step explanation:
Answer:
Subset is part of set which is obtained from Universal set.
Step-by-step explanation:
Like for example :-
A - ( 1,2,3,4,5,6,7,8)
And B - ( 1,2 , 3)
So we can say B is subset of A.
Last Question
Because this may not be the question you want, I'll omit the first step which should be done with latex. The key to all of these except C is to invert the second fraction (turn the second fraction upside down) and multiply.
A
=(6*-2) / (5*3) = - 12/15 = -4/5
B
= (7*5) / (4*3) = 35 / 12 = 2 11/12
C
Impossible to do 4/0 cannot be done.
D
= (-2*-4)/(3*5) =
8/15
