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Shalnov [3]
3 years ago
8

what is the solution to this system of linear equations? 2x y = 1 3x – y = –6 (–1, 3) (1, –1) (2, 3) (5, 0)

Mathematics
2 answers:
Nitella [24]3 years ago
8 0
Hello,

2x+y=1
3x-y=-6

==>5x=-5
==>x=-1 and y=1-2*(-1)=3
Sol={(-1,3)}

Answer A

kicyunya [14]3 years ago
3 0

Answer:

A

Step-by-step explanation:

E2020...............................:)

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Given:
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3 years ago
Read 2 more answers
Show your solution read the instructions​
Annette [7]

Answer:

1) 5r + 2 < s

2) 12t + 6s < 960

3) p - q > 30

Step-by-step explanation:

1) Length of a ruler = r

Height of Shiela = s

According to the question ,

5 times the length of a ruler increased by 2 .

⇒ 5r + 2

Also , 5r + 2 is less than height of Shiela.

Hence , the linear inequality is ⇒ 5r + 2 < s

2) Let the cost of each t-shirt be 't' & cost of each short be 's'.

⇒ Cost of dozen of t-shirts = 12t and Cost of half a dozen shorts = 6s

According to the question ,

12t & 6s is not greater than Php 960.

Hence the linear inequality is ⇒ 12t + 6s < 960

3) Let the number of Php 100-peso tickets be 'p' and let the number of Php  50-peso tickets be 'q'.

According to the question ,

Difference of p & q is not less than 30

Hence the linear inequality is ⇒p - q > 30

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2 years ago
The coefficient of xy in the product of (4x^2y+)and(3x+y^2) is
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3 years ago
Which statements about the histogram are true? Check all that apply.
Ipatiy [6.2K]

Answer:

the other person is wrong, its b, d, e, and f

Step-by-step explanation:

8 0
3 years ago
Please explain how to solve this (<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Ba%5E5%20b%5E3%7D%20" id="TexFormula1" ti
olchik [2.2K]
2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

(\sqrt[4][a*a*a*a*a*b*b*b]) there is one group of 4 a's so

(a\sqrt[4][a* b^3])

there really isn't anything else to do to simplify the expression
5 0
2 years ago
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