Problem A
Usually the number of bits in a byte is 8 or 16 or 32 and recently 64. You don't have to write a formula to restrict it to this number of bits. You are not asked to do so. The general formula is 2^n - 1 for the problem of Millie and her golden keys. Somehow the system can be made to choose the right number of bits. Apple IIe s for example, used 8 bits and there was a location that told the processor that fact.

2^n - 1 <<<<< Answer

Problem B
In this case n = 4
2^n - 1 = 2^4 - 1 = 16 - 1 = 15

Millie can collect 15 keys <<<<<< Answer

5 0

3 years ago

What are the ordered pairs of the

OlgaM077 [116]

Answer:

The two points solutions to the system of equations are: (2, 3) and (-1,6)

Step-by-step explanation:

These system of equations consists of a parabola and a line. We need to find the points at which they intersect:

$x^2-2x+3=-x+5\\x^2-2x+x+3-5=0\\x^2-x-2=0\\(x-2)(x+1)=0$

Since we were able to factor out the quadratic expression, we can say that the x-values solution of the system are:

x = 2 and x = -1

Now, the associated y values we can get using either of the original equations for the system. We pick to use the linear equation for example:

when x = 2 then $y=-(2)+5=3$

when x= -1 then $y=-(-1)+5=6$

Then the two points solutions to the system of equations are: (2, 3) and (-1,6)

6 0

3 years ago

Give an example of a rational function that has a horizontal asymptote at y = 0 and a vertical asymptote at

Vesnalui [34]

F(x)=x^2/(x-2)(x-1), the degree of the numerator and the degree of the denominator equal and the quotient of their coefficient equal to 1(horizontal asymptote means that the lines approach a certain number when the input approaches positive or negative infinity)
and when plugging in 2 or 1 as input, the output is undefined.

8 0

3 years ago

Read 2 more answers

Hint: You won't flip the sign in every problem. ONLY FUP it when you or by a 9 - 2x < 6x - 15 Solutions You solve and graph t

svetoff [14.1K]

You only flip the inequality sign when you multiply or divide both sides by a negative number.

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Problem 1

$3 - 8x \ge -29\\\\-8x \ge -29-3\\\\-8x \ge -32\\\\x \le \frac{-32}{-8} \ \text{ inequality sign flip}\\\\x \le 4$

The inequality sign flip happens because we divided both sides by -8.

The graph will have a closed circle at 4 with shading to the left.

Three solutions are x = 0, x = 1, x = 2. You can pick any three numbers you want as long as they are 4 or smaller.

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Problem 2

$1x+2x-7 < 6\\\\3x-7 < 6\\\\3x < 6+7\\\\3x < 13\\\\x < \frac{13}{3}\\\\x < 4 \frac{1}{3}$

The graph will have an open circle at 13/3 = 4&1/3 = 4.333 approx. The shading is to the left. No inequality sign flip happens because we divided both sides by a positive number.

Your choice of three solutions is correct. You can pick anything smaller than 4.3333

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Problem 3

$9-2x \le 6x-15\\\\-2x-6x \le -15-9\\\\-8x \le -24\\\\x \ge \frac{-24}{-8} \ \text{ inequality sign flip}\\\\x \ge 3$

The solution set is any value 3 or larger. Three solutions are x = 5, x = 6 and x = 7.

The graph has a closed circle at 3 on the number line. The shading is to the right.

8 0

3 years ago