Answer: a) P(x=0) = 0.0907, b) P(x≥10) = 0.7986
Step-by-step explanation: the probability mass function of a possion probability distribution is given as
P(x=r) = (e^-λ)×(λ^r) /r!
Where λ = fixed rate at which the event is occurring and each event is independent of each other = 2.4
a) P(x= at least one) = P(x≥1)
P(x≥1) = 1 - P(x<1)
But P(x<1) = P(x=0) { we can not continue to negative values because our values of x can only take positive values of integer}
Hence, P(x≥1) = 1 - P(x=0)
P(x=0) = e^-2.4 * 2.4^0/(0!)
P(x=0) = 0.0907×1/1
P(x=0) = 0.0907
b) if the average number of hits in 1 minutes is 2.4 then for 5 minutes we have 2.4×5 = 12.
Hence λ = 12.
P(x= at least 10) =P(x≥10) = 1 - P(x≤9)
P(x≤9) will be gotten using a cumulative possion probability distribution table whose area is to the left of the distribution.
From the table P(x≤9) = 0.2014.
P(x≥10) = 1 - 0.20140
P(x≥10) = 0.7986
Answer:
719.4244604
Step-by-step explanation:
100/0.139=719.4244604
" · " - product
" - " - difference
13 · (8 - (-10)) = 13 · (8 + 10) = 13 · 18 = 234
Mean weight of the bag of pears = u = 8 pounds
Standard deviation = s = 0.5 pounds
We have to find what percentage of bags of pears will weigh more than 8.25 pounds. This can be done using the z score.
We have to convert x = 8.25 to z scores, which will be:
z score = 0.5From the z table, the probability of z score being greater than 0.5 is 0.3085
Therefore, the probability of a bag to weigh more than 8.25 pounds is 0.3085
Thus 0.3085 or 31% (rounded to nearest integer) of bags of pears will have weight more than 8.25 pounds at the local market.
Answer:
Area of first shape is 288
, area of second shape is 45
, area of third shape is 34
.
Step-by-step explanation:
Area of first shape
A=bh
A=18*16
A=288
Second shape
A=bh
A=9*5
A=45
Third shape
A= 1/2 h(b1+b2)
A=1/24(12+5)
A=1/2*4(12+5)
A=1/2*4(17)
A=1/2*68
A=34