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3 years ago

Find the value of x

Mathematics

2 answers:

adelina 88 [10]3 years ago

6 0

Answer:0.3

Step-by-step explanation:

(7x+0.1)+(10x-0.2)= 17x-0.1

17x-0.1=5

17x=5.1

x=5.1/17

x=0.3

Lorico [155]3 years ago

6 0

Answer : The value of 'x' is, 0.3

Step-by-step explanation :

Given:

Length of AN = 5 unit

Length of AM = 7x+0.1

Length of MN = 10x-0.2

Now we have to determine the value of 'x'.

Length of AN = Length of AM + Length of MN

Now put all the given values in this expression, we get the value of 'x'.

5 = (7x+0.1) + (10x-0.2)

5 = 7x + 0.1 + 10x - 0.2

5 = 17x - 0.1

5 + 0.1 = 17x

5.1 = 17x

x = 5.1/17

x = 0.3

Therefore, the value of 'x' is 0.3

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Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

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see the attached figure

step 2

Find the perimeter

we know that

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$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

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we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

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Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

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we have

C(27,-8),D(-4,9)

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$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

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we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

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$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

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$P=135.4\ units$

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The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

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3 years ago

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2 years ago

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Answer:

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3 years ago