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3 years ago

Y=4x+8 Y=5x+1 I cant figure out this math problem

1 answer:

Crank3 years ago

4 0

If solving for x:
Because both equations are equal to Y, you can set both equations equal to each other:
5x+1=4x+8
Then it's a matter of simplification (subtract the 4x to the left side and subtract the 1 over to the right):
x=7
If solving for Y:
Plug x=7 into either equation and solve:
Y=4(7)+8
Y=36

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You will be brainliest please list correct answer and the mistake he made

anzhelika [568]

<em>Hey There!!</em>

<em>The answer is below!!</em>

Step-by-step explanation:

We move all terms to the left:

$-6n+22-(-4n+14-10n+22)=0$

We add all the numbers together, and all the variables

$-6n-(-14n+36)+22=0$

We get rid of parentheses

$-6n+14n-36+22=0$

After that, We add all the numbers together, and all the variables

$8n-14=0$

Then, We move all terms containing n to the left, all other terms to the right

$8n=14$

$n=14/8$

$n=1+3/4$

<em>I don't know this is </em> $100$ % right....

$So.....GoodLuck!!$

# $Be$ $Bold$

# $Always$ $Brainly!$

$_{Loserbrazts}$

5 0

3 years ago

Plz answer.............

spayn [35]

Answer:

( - x, - y )

Step-by-step explanation:

The starting is always Quadrant I.

270 degrees clockwise from Quadrant I is Quadrant III.

In Quadrant III, the points will be in the form ( - x, - y ).

7 0

3 years ago

Will mark brainliest!! Please answer ASAP

rusak2 [61]

Answer:

y=5

Step-by-step explanation:

y= 5 is always parallel to x axis

8 0

3 years ago

For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The

Tema [17]

Answer:

Number of cheaper dresses sold is 35

Number of expensive dresses sold is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of expensive dresses = $140

Total cost of the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive dress = ?

Solution:

Let

The number of cheaper dresses be x

The number of expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) + (Number of Expensive dresses X cost of expensive dress) = $5250

$x \times90 +y \times 140 = 5250$ = $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress = 20 + number of expensive dress

x = 20 + y---------------------------------------(1)

$(20+y) \times90 +y \times 140 = 5250 = 5250$

$(20 \times 90 +y\times 90) +y \times 140= 5250$

$1800 + 90y+ 140y = 5250$

$1800 + 230y = 5250$

$230y =5250 -1800$

$230y = 3450$

$y = \frac{3450}{230}$

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0

3 years ago

Simplify: (7+2a)·3–20 =

Black_prince [1.1K]

<h2>Greetings!</h2>

Answer:

6a + 1

Step-by-step explanation:

First, you need to multiply everything in the brackets by 3L

(7 + 2a) x 3 =

7 * 3 = 21

2a * 3 = 6a

21 + 6a

Now you can subtract the 20 from this:

6a + 21 - 20

Simplified down:

6a + 1

<h2>Hope this helps!</h2>

6 0

3 years ago