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attashe74 [19]
3 years ago
9

Y=4x+8 Y=5x+1 I cant figure out this math problem

Mathematics
1 answer:
Crank3 years ago
4 0
If solving for x:
Because both equations are equal to Y, you can set both equations equal to each other:
5x+1=4x+8
Then it's a matter of simplification (subtract the 4x to the left side and subtract the 1 over to the right):
x=7
If solving for Y:
Plug x=7 into either equation and solve:
Y=4(7)+8
Y=36
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How many real solutions does the equation 8x^2 − 10x + 15 = 0 have?
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Answer:

The correct option is (A) No real solution.

Step-by-step explanation:

The expression provided is a quadratic equation.

8x^{2}-10x+15=0

The roots of a quadratic equation are:

x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }

Here,

a = 8

b = -10

c = 15

The conditions to determine real and complex roots are:

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Compute the value of b^{2}-4ac as follows:

b^{2}-4ac=(-10)^{2}-(4\times 8\times15)\\\\

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The equation has two complex roots.

Thus, the correct option is (A).

8 0
3 years ago
* PLEASE HELP *
LiRa [457]
The first one is 135 per hour if you barely went 90 miles in a hour in a half, and the second one it is 1/3+1/3+1/3 you add 2 more thirds so it means you add 2 forths 1/4/+1/4+1/4=3/4 so you paint 3/4's of the wall
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Hola amigos, como estas! I need some with with this: If you have a bowl with 27 apples and you take away four, how many do you h
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You will have 23 apples left

Step-by-step explanation:

Because 27-4=23 apples

So the answer is 23 apples

<em>Hope I Helped Amigo</em>

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