Answer:
How do you figure out if a relation is a function? You could set up the relation as a table of ordered pairs. Then, test to see if each element in the domain is matched with exactly one element in the range. If so, you have a function!
Step-by-step explanation:
Answer:
3.5 hours
Step-by-step explanation:
Ediburgh -------------------------------350 miles-------------------------London
Let the distance traveled by train from Edin to London be "x"
hence the distance traveled by train from London to Edin would be "350-x"
- The rate of Edin to London train is 60
- The rate of London to Edin train is 40
Let the time they meet be"t"
Now, we know distance formula to be D = RT
Where
D is distance
R is rate
and
T is time
<u>Train from Edin to London:</u>
x = 60t
<u>Train from London to Edin:</u>
350-x = 40t
Solving for x:
350 - 40t = x
We put this into first equation:
x = 60t
350 - 40t = 60t
350 = 100t
t = 350/100
t = 3.5
They meet after 3.5 hours
Answer:x = 164686.592598
Step-by-step explanation:
219379.01−x/x = 0.3321
−x+219379.01/x = 0.3321
Step 1: Multiply both sides by x.
−x+219379.01≈0.3321x
−x+219379.01 − 0.3321x = 0.3321x−0.3321x (Subtract 0.3321x from both sides)
−1.3321x + 219379.01 = 0
−1.3321x + 219379.01 − 219379.01 = 0 − 219379.01 (Subtract 219379.01 from both sides)
−1.3321x = −219379.01
−1.3321x/−1.3321 = −219379.01/−1.3321
(Divide both sides by -1.3321)
x = 164686.592598
Well you could do 5(60x+20y), 100(3x+y), and 2(150x+50y)