The complete factorization of the equation 81x² - 100 is; (9x - 10)(9x + 10)
<h3>How to factorize quadratic equations?</h3>
We are given the quadratic equation;
81x² - 100
Now, according to quadratic identities, we know that;
(a + b) * (a - b) = a² - b²
Now, our equation can also be expressed as;
81x² - 100 = 9²x² - 10²
Thus, applying the quadratic identity gives us;
(9x + 10)(9x - 10)
Read more about factorization of quadratic equations at; brainly.com/question/1214333
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Answer:
x > 6
Step-by-step explanation:
1.) Distribute - 3 through the parenthesis
7x-3(4x-8)<6x+12-9x
7x-12x+24<6x+12-9x
2.) Then collect like terms
7x-12x+24<6x+12-9x
7x-12x+24<-3x+12
7x-12x+24<-3x+12
-5x+24<-3x+12
3.) Move the <u>variable</u> to the left and change the sign
-5x+24<-3x+12
-5x+3x+24<12
4.) Move the <u>constant</u> to the right and change it's sign
-5x+3x+24<12
-5x+3x<12-24
5.) Collect like terms
-5x+3x<12-24
-2x<12-24
6.) Calculate the difference
-2x<-12
7.) Divide both sides by -2 and flip the inequality sign
-2x<-12
x>6
Answer: 34
Step-by-step explanation:
First do the equation between "[" and "]". (-7+5=-2) Then divide. (-12/-2=6) Then do the multiplication. (-7*4=-28) Subtract the last two numbers. (6-(-28)=34)
the answer for one is C
the answers for 2 is the first choice, third choice and last choice
the answer for three is D
Answer:
round it to the nearest 10th?
Step-by-step explanation:
that's what I do at least.