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Andrej [43]
2 years ago
13

How do you do f(x)=12x+3 2units leftg(x)=please help I'm confused ​

Mathematics
1 answer:
Mkey [24]2 years ago
7 0

Answer:

g(x) = 12x + 27

Step-by-step explanation:

Take a point in the f(x).

f(0) = 12(0) + 3

f(0) = 3

A point on f(x) is (0,3).

Move the point 2 units left. It will make the x-coordinate decrease by 2.

0 - 2 = -2

A point on g(x) is (-2,3).

Substitute the point and the same slope into the equation of a line. The slope did not change.

y = mx + b

3 = 12(-2) + b

3 = -24 + b

b = 3 + 24

b = 27

Rewrite g(x) using b = 27 and the same slope, m = 12.

g(x) = 12x + 27

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Expand and simplify (3X+1)(2X+4)​
nordsb [41]

Answer:

6x square +14x+4

Step-by-step explanation:

hope this helps................

5 0
2 years ago
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The Graph describes the water level of creek after a rainstorm which best describes the domain in context?
belka [17]

The domain of a function are its possible input values

The domain of the function is <em>(b) all real numbers greater than or equal to 0.</em>

From the graph, we have the following observations

  • <em>t represents time (it is plotted on the x-axis)</em>
  • <em>t starts at 0</em>
  • <em>t has no end</em>

The above observations imply that; the domain starts from 0

Hence, the domain of the function is the set of all real numbers greater than or equal to 0.

Read more about domain at:

brainly.com/question/2709928

5 0
1 year ago
A rectangular package sent by a postal service can have a maximum combined length and girth (perimeter of a cross sectio) of 108
Morgarella [4.7K]

Answer:

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

Step-by-step explanation:

This is a optimization with restrictions problem.

The restriction is that the perimeter of the square cross section plus the length is equal to 108 inches (as we will maximize the volume, we wil use the maximum of length and cross section perimeter).

This restriction can be expressed as:

4x+L=108

being x: the side of the square of the cross section and L: length of the package.

The volume, that we want to maximize, is:

V=x^2L

If we express L in function of x using the restriction equation, we get:

4x+L=108\\\\L=108-4x

We replace L in the volume formula and we get

V=x^2L=x^2*(108-4x)=-4x^3+108x^2

To maximize the volume we derive and equal to 0

\dfrac{dV}{dx}=-4*3x^2+108*2x=0\\\\\\-12x^2+216x=0\\\\-12x+216=0\\\\12x=216\\\\x=216/12=18

We can replace x to calculate L:

L=108-4x=108-4*18=108-72=36

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

4 0
3 years ago
Read 2 more answers
Will give brainliest ^-^
ANEK [815]

area of square = 9 x 9 = 81 square feet


 area of 1 corner = 1/2 * 3 * 3 = 4.5 square feet

4.5 * 4 = 18 square feet total of all 4 corners

81 - 18 = 63 square feet total not covered by benches.


Please mark Brainliest.


3 0
3 years ago
Read 2 more answers
Bowl A contains 6 apples and 3 mangoes this can be written as, Bowl B contain 8 apples and 2 mangoes this can be written as. Wha
Andrew [12]

Answer:

Bowl B contains 2 apples more than Bowl A and Bowl A contains 1 mango more than Bowl B.

Step-by-step explanation:

Number of apples in Bowl A = 6

Number of mangoes in Bowl B = 8

Difference in apples = 8 - 6 = 2

So, Bowl B contains 2 apples more than Bowl A.

Number of mangoes in Bowl A = 3

Number of mangoes in Bowl B =2

Difference in mangoes = 3 - 2 = 1

So, Bowl A contains 1 mango more than Bowl B.

3 0
2 years ago
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