Answer: Third one, p = 0.303
Explanation: We know that, for the males, we have:
10 with brown eyes, 2 with blue eyes, 9 with hazel eyes and 12 with grey eyes.
This adds to a total of 10 + 2 + 9 + 12 = 33 total male students.
If we choose a random male student, we are choosing one of the 33 male students.
Then the probability that the chosen student has brown eyes is equal to the number of students with brown eyes divided by the total number of male students:
p = 10/33 = 0.303
Then the right option is the third one.