P(x)=-15+7/4=-2
P(y)=12-4/4=2
P=(-2,2)
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
The most relevant answer is B
She will get 23 books.
So, first, you take the shipping away to get $93.05,
then you divide $93.05 by $3.95 which equals 23.55
and you can't have half a book; so it's 23!
Answer: The first option.
Step-by-step explanation:
1. You need to remember that:
- An even function is a function with the following property:
f(-x)=f(x)
- An odd function is a function with the following property:
f(-x)=-f(x)
2. By definition, the contangent is an odd function, therefore you have that:
cot(-θ)=-cot(θ)
Then:
3. So, you can coclude that the first step is wrong. Therefore, the answer is the first option.
