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3 years ago

Show your work plzz :))))

Mathematics

2 answers:

BaLLatris [955]3 years ago

7 0

Here I can answer so the other person can get brainliest

ankoles [38]3 years ago

6 0

Answer:

9/10

Step-by-step explanation:

1/6 hour for 3/20 of his yard

6/6 hour or 1 hour = 6* 3/20 = 9/10 of his yard per hour

Mark as brainliest if this helped

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On a coordinate plane, a triangle is shown. It has points A prime (4, 2), B prime (8, negative 8), and C prime (4, negative 8).

gogolik [260]

Answer: A

Explaining: Because A actually shows all the steps and work. And it’s the more realest android.

4 0

3 years ago

Read 2 more answers

The area of a trapezoid is 60 square feet. If the bases of the trapezoid are 8 feet and 12 feet, what is the height?

Margarita [4]

Answer:

Step-by-step explanation:

60 = 12+8 divided 2 times height

60 = 20/2 x H

60 = 10 x H

60/10 = h

6 = H

7 0

3 years ago

the diameter of the sweep of the main rotor of the eh101 helicopter is 18.6 meters. A toy model of it has a sweep of 31 centimet

Aliun [14]

Answer:

The actual length of 60 cm is modeled as 1 cm length.

Step-by-step explanation:

The diameter of the sweep of the main rotor of the helicopter is 18.6 meters i.e. 1860 cm.

Now, the toy model of the helicopter has a sweep of 31 cm.

Therefore, the scale in which the model is made is 1860 : 31 i.e. 60 : 1 ratio.

So, the actual length of 60 cm is modeled as 1 cm length. (Answer)

4 0

3 years ago

Read 2 more answers

What number am I?

Rudik [331]

Answer:

Step-by-step explanation:

The first digit is 9

the 2nd one from the right = 2

So far what you have is

911, 121

941,121

There seems to be a second 4 implied. What is it? I'll edit if you get it to me in the next hour.

6 0

3 years ago

Classify ABC by its sides. Then determine whether it is a right triangle.

m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

$AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

AB = $\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}$

Given vertices are B(6,9) and C( 6,-3)

$B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

= $\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12$

BC = 12

Given vertices are A(3,3) and C( 6,-3)

$AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}$

AC² = AB²+BC²

45 = 45+144

45 ≠ 189

∴Given Δ ABC is not a right angle triangle

5 0

3 years ago