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ArbitrLikvidat [17]
3 years ago
8

754.30-440.80= what percent

Mathematics
1 answer:
alex41 [277]3 years ago
7 0
754.30:440.80<span>*100 and thats the answer i think</span>
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Alex has 520 yards of fencing to enclose a rectangular area.
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<span>Perimeter =2w+2L= 520.
We can solve this by understanding that the area is maximized by a square
Therefore L=w.

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3 years ago
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A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib
Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 502, \sigma = 115

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

Z = \frac{X - \mu}{\sigma}

Z = \frac{590 - 502}{115}

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

Z = \frac{X - \mu}{\sigma}

Z = \frac{400 - 502}{115}

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

#SPJ1

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2 years ago
Yo if u need an bralest i got chu
dybincka [34]

Answer:

PLease

Step-by-step explanation:

4 0
3 years ago
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3 years ago
The width of a rectangle is 3 yards less than its length. The perimeter is 130 yards. Find the length and width of the rectangle
topjm [15]

Answer: length = 62 yards and width = 3 yards

Step-by-step explanation:

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2 years ago
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