3 years ago

Plzzzz helppppppppp and free kodak

2 answers:

7 0

Answer:

77.77

Step-by-step explanation:

you subtract 16 (prediction) - 9 (actual) and divide it by the actual.

5 0

Free kodak they wanna see him in the penetration ✊

You might be interested in

SVEN [57.7K]

Given $p,q>0$ and $\log_9p=\log_{12}q=\log_{16}(p+q)=x$ (say).

Then,

$p=9^x\\ q=12^x\\ p+q=16^x$

From the above 3 equations,

$\frac{q}{p} =(\frac{12}{9} )^x\\ \frac{q}{p} =(\frac{4}{3} )^x\\ \frac{p+q}{p} =(\frac{16}{9} )^x\\ \frac{p+q}{p} =(\frac{4}{3} )^{2x}\\$

From the equations, we get

$\frac{p+q}{p}=(\frac{q}{p})^2\\ 1+\frac{q}{p}=(\frac{q}{p})^2\\ (\frac{q}{p})^2-\frac{q}{p}-1=0\\ \frac{q}{p}=\frac{1 \pm \sqrt{5}}{2}$

Since $p,q>0$ , the negative value is rejected.

$\frac{q}{p}=\frac{1 + \sqrt{5}}{2}$

3 0

3 years ago

WINSTONCH [101]

   C = 2πr
   17 = 2(3.14)(r)
   17 = 2(3.14r)
   17 = 6.28r
6.28   6.28
2.71 ≈ r

5 0

3 years ago

Orlov [11]

6x + 1 = 13

Hope this helps!

6 0

3 years ago

Sever21 [200]

12.96 is the answer.

6 0

2 years ago

zhuklara [117]

Its B, The answer for your question is B

4 0

2 years ago