Answer:
402 days.
Step-by-step explanation:
f(x)=1+1.5ln(x+1)
When f() = 10 we have:
10 = 1 + 1.5ln (x + 1)
ln (x + 1) = (10-1) / 1.5 = 6
x + 1 = e^6
x = e^6 - 1 = 402.4.
Answer:
/
Step-by-step explanation:
firstly we make two steps to simplify this question.
1st step: simplify 
to simplify this we use factorization


.....(1)
2nd step:simplify 


.....(2)
now dividing (1) and (2), we get the answer

Answer:
12/30 or 6/15
Step-by-step explanation:
3x4=12
5x6=30
12/30
simplified would be 12/30 divided by 2/2
the answer is 6/15
<span>(1,625) No
(0,-25) No
(-1,-1) No
Think about what an integer exponent means for an negative base and you'll understand this problem. For instance the powers of -25 would be
-25^1 = -25
-25^2 = (-25) * (-25) = 625
-25^3 = (-25)*(-25)*(-25) = -15625
and so on, giving 390625, -9765625, 244140625, etc.
But that's a different subject. For the ordered pairs given, let's check them out.
(1,625)
-25^1 + 1 = -25 + 1 = -24. And -24 is not equal to 625, so "No".
(0,-25)
-25^0 + 1 = 1 +1 = 2.
Note: Any real number other than 0 raised to the 0th power is 1. And 2 is not equal to -25, so "No".
(-1,-1)
-25^(-1) + 1 = 1/(-25^1) + 1 = 1/-25 + 1 = 24/25.
And 24/25 is not equal to -1, so also "No".</span>
Answer:
Therefore they are 734.106 miles apart.
Step-by-step explanation:
Given that ,
Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.
It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.
Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles
Then the distance between the ships = AC
We know
The sum of all angles = 180°
⇒∠A+∠B+∠C=180°
⇒∠A+135°40'+∠C=180°
⇒2∠A= 180°- 135°40' [ since ∠A=∠C]
⇒2∠A=44°60'
⇒∠A= 22°30'
Again we know that,

Taking last two ratio,

Putting the value of BC , AC ,∠A,∠B


≈734.106 miles
Therefore they are 734.106 miles apart.